Kotlin-将列表转换为MutableList的最惯用方式 [英] Kotlin - Most idiomatic way to convert a List to a MutableList

问题描述

我有一个返回List<Contact>的方法(getContacts)，我需要将此结果转换为MutableList<Contact>.目前，我能想到的最好方法是这样的:

I have a method (getContacts) that returns a List<Contact> and I need to convert this result to a MutableList<Contact>. Currently the best way I can think of doing it is like this:

val contacts: MutableList<Contact> = ArrayList(presenter.getContacts())

是否有更惯用的/更少的Java"?做到这一点的方法?

Is there a more idiomatic/"less Java" way to do that?

推荐答案

请考虑使用

Consider using the toMutableList() function:

presenter.getContacts().toMutableList()

可能要转换为可变列表的stdlib类型具有toMutableList()扩展名:Collection<T>，Iterable<T>，Sequence<T>，CharSequence，Array<T>和原始数组.

There are toMutableList() extensions for the stdlib types that one might want to convert to a mutable list: Collection<T>, Iterable<T>, Sequence<T>, CharSequence, Array<T> and primitive arrays.

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