如何使用scrapy处理escaped_fragment [英] how to deal with escaped_fragment using scrapy
问题描述
最近我用scrapy刮了zoominfo,然后测试了以下网址
recently i used scrapy to scrape zoominfo then i test the below url
http://subscriber.zoominfo.com/zoominfo/#!search/profile/person?personId=521850874&targetid=profile
但是在终端中有些变化,就像这样
but some how in terminal, it changed like this
[scrapy] DEBUG: Crawled (200) <GET http://subscriber.zoominfo.com/zoominfo/?_escaped_fragment_=search%2Fprofile%2Fperson%3FpersonId%3D521850874%26targetid%3Dprofile>
我在 setting.py
中添加了 AJAXCRAWL_ENABLED = True
,但该网址仍然具有 escaped_fragment
.我怀疑我没有输入正确的页面.
I have added AJAXCRAWL_ENABLED = True
in setting.py
but the url still has escaped_fragment
. I doubt that i haven't entered the right page i want.
spider.py 代码如下:
The spider.py
code is below:
#!/usr/bin/env python
# -*- coding:utf-8 -*-
import scrapy
from scrapy.selector import Selector
from scrapy.http import Request, FormRequest
from tutorial.items import TutorialItem
from scrapy.spiders.init import InitSpider
class LoginSpider(InitSpider):
name = 'zoominfo'
login_page = 'https://www.zoominfo.com/login'
start_urls = [
'http://subscriber.zoominfo.com/zoominfo/#!search/profile/person?personId=521850874&targetid=profile',
]
headers = {
"Accept":"text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8",
"Accept-Encoding":"gzip, deflate, br",
"Accept-Language":"en-US,en;q=0.5",
"Connectionc":"keep-alive",
"User-Agent":"Mozilla/5.0 (Macintosh; Intel Mac OS X 10.12; rv:50.0) Gecko/20100101 Firefox/50.0",
}
def init_request(self):
return Request(url=self.login_page, callback=self.login)
def login(self, response):
print "Preparing Login"
return FormRequest.from_response(
response,
headers=self.headers,
formdata={
'task':'save',
'redirect':'http://subscriber.zoominfo.com/zoominfo/#!search/profile/person?personId=521850874&targetid=profile',
'username': username,
'password': password
},
callback=self.after_login,
dont_filter = True,
)
def after_login(self, response):
if "authentication failed" in response.body:
self.log("Login unsuccessful")
else:
self.log(":Login Successfully")
self.initialized()
return Request(url='http://subscriber.zoominfo.com/zoominfo/', callback=self.parse)
def parse(self, response):
base_url = 'http://subscriber.zoominfo.com/zoominfo/#!search/profile/person?personId=521850874&targetid=profile'
sel = Selector(response)
item = TutorialItem()
divs = sel.xpath("//div[3]//p").extract()
item['title'] = sel.xpath("//div[3]")
print divs
request = Request(base_url, callback=self.parse)
yield request
感谢任何人都可以给我提示.
thanks anyone could give me a hint.
推荐答案
#!
== _escaped_fragment _
_escaped_fragment _
被称为丑陋的url,主要呈现给网络爬虫,而真实用户则获得漂亮的#!
版本.无论哪种方式,它们都意味着同一件事,并且在功能上应该没有任何不同.
_escaped_fragment_
is called ugly url and is mostly presented to web-crawler while real users get the pretty #!
version. Either way they both mean the same thing and there shouln't be any different functionally.
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