如果页面是使用PHP中的ajax加载的.页面加载后如何调用函数 [英] if a page is loaded using ajax from PHP. how to call a function if page is loaded

问题描述

我正在研究php + ajax.有人可以在后续过程中帮助我吗

i'm working on php + ajax. can somebody help me in following process

1. 我做了两个div(一个包含manu，另一个是目标div，从菜单中加载页面)
2. 我在terget div中加载了一个.
3. 此表单使用php向数据库添加值.
4. 由于数据已成功保存 ...在目标div中，因此下一页进行了响应
5. 现在我想在文本显示为"数据保存成功"之后立即调用javascript函数.
6. 此功能将用户带到下一个表格...
   如果还有其他解决方案，请告诉我.谢谢你

1. I made two divs (one contains manu, and other is target div, where pages are loaded from menu)
2. i loaded a from in terget div.
3. this form adds values to database using php.
4. the next pages respondeds as data is saved successfully... in target div
5. now i want to call a javascript function right after text appears "data is saved successfully".
6. this function takes the user to the next form...
   if there is any other solution please do let me know. thank you

推荐答案

您将像执行任何标准AJAX一样进行操作:

You would do it just like any standard AJAX:

设置AJAX成功调用函数，以检查PHP代码返回的任何状态代码.如果状态代码成功，则执行您想做的事情-在这种情况下，请调用Javascript函数.

set up the call back function for the AJAX success to check for any status code returned by the PHP code. If the status code is a success, then do what you want to -- in your case, call the Javascript function.

通常，使用某些Javascript库(例如jQuery的AJAX)会更容易:

usually it is easier to use some Javascript library, such as jQuery's AJAX:

http://api.jquery.com/jQuery.ajax/

查找成功(数据，textStatus，jqXHR)，这是回调函数及其示例.

look for the success(data, textStatus, jqXHR) which is the callback function and the examples there.

请注意，状态码404或200与您自己的状态码不同.您的状态码可以是作为AJAX调用内容返回的任何内容.通常，通常会返回200的状态代码，但这是HTTP的代码，而不是您的状态代码.

note that the status code 404 or 200 is different from your own status code. Your status code can be anything returned as the content of the AJAX call. Usually, a typical status code of 200 is returned, but that's the code for HTTP, not your status code.

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