使用ajax show打开新窗口 [英] using ajax show open new window
问题描述
在此代码中有一些与链接有关的错误，它没有打开页面.我提供的链接中可能有错误，并且没有显示警告，其中有其他链接的数据页面.在我的PC中，文件的链接为"D:\ xampp \ htdocs \ cart \ welcome.php"，这意味着其在文件夹"D:\ xampp \ htdocs \ cart"中，现在我进行了更改以使其正确，我在我的电脑上使用xampp来使用它，不会使网站
in this code there is some error related to the link and it is not opening the page .there error may be in the link that i am giving and it is not showing the alert in which it will have the data of the other page .in my pc the link of the file is "D:\xampp\htdocs\cart\welcome.php" means its in folder "D:\xampp\htdocs\cart" now what i change to make it right and i am using this on my pc with xampp not making webstie
<html>
<head>
<script>
function check(form) {
if (form.email.value == "id@gmail.com") {
document.getElementById("displayu").innerHTML ="correct username".fontcolor("green");
} else if (form.email.value == "") {
document.getElementById("displayu").innerHTML ="<font color='red'>blank username</font>";
} else if (form.email.value != "") {
var email = document.getElementById('email');
var filter = /^([a-zA-Z0-9_\.\-])+\@(([a-zA-Z0-9\-])+\.)+([a-zA-Z0-9]{2,4})+$/;
if (!filter.test(email.value)) {
document.getElementById("displayu").innerHTML ="Please provide a valid email address";
}
else {document.getElementById("displayu").innerHTML ="wrong email";}
}
if (form.pswrd.value == "123") {
document.getElementById("displayp").innerHTML ="correct password";
} else if (form.pswrd.value == "") {
document.getElementById("displayp").innerHTML ="<span style='color:red'>blank password</span>";
}
else {document.getElementById("displayp").innerHTML ="wrong password";}
makeRequest('http://D:/xampp/htdocs/cart/welcome.php');
}
function makeRequest(url) {
httpRequest = new XMLHttpRequest();
if (!httpRequest) {
alert('Giving up :( Cannot create an XMLHTTP instance');
return false;
}
httpRequest.onreadystatechange = alertContents;
httpRequest.open('GET', url);
httpRequest.send();
}
function alertContents() {
if (httpRequest.readyState === XMLHttpRequest.DONE) {
if (httpRequest.status === 200) {
alert(httpRequest.responseText);
document.open();
document.write(httpRequest.responseText);
document.close();
} else {
alert('There was a problem with the request.');
}
}
}
</script>
</head>
<body>
<h1>for login</h1>
<h3>email=id@gmail.com and password=123</h3>
<form name="login">
<div id="displayu"></div>
<div id="displayp"></div>
Username <input type="text" name="email" id="email" />
Password <input type="password" name="pswrd"/>
<input type="button" onclick="check(this.form)" value="Login" />
<input type="reset" value="reset"/>
</form>
</body>
</html>推荐答案
您需要运行Web服务器，然后使用网络名称(例如 http://localhost/cart/welcome.php)从中请求资源.).
You need to run a webserver and then request your resource from that using a network name (e.g. http://localhost/cart/welcome.php).
指向本地文件路径的URL将以 file:而不是 http:开头，但是XMLHttpRequest的大多数实现都会拒绝支持它，并且不会导致要执行的PHP(因为在这种情况下，PHP是一种服务器端编程语言).
A URL to a local filepath would start with file: instead of http:, but most implementations of XMLHttpRequest would refuse to support it, and it wouldn't cause the PHP to be executed (since PHP, in this context, is a server side programming language).
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