如何找到树的分支因子 [英] How to Find the Branching Factor of a Tree
问题描述
一个特定的搜索树在第3层有6个节点.在下一个层,有24个节点.级别3的分支因子是多少?
A particular search tree has 6 nodes at level 3. At the next level, there are 24 nodes. What is the branching factor at level 3?
答案是4,但是有人可以告诉我为什么,我认为是2.
The answer is 4, but can someone tell me why, I thought that it was 2.
推荐答案
来自维基百科:
在计算,树数据结构和博弈论中,分支因子是每个节点上的子代数,即度数.如果该值不均匀,则可以计算平均分支因子.
In computing, tree data structures, and game theory, the branching factor is the number of children at each node, the outdegree. If this value is not uniform, an average branching factor can be calculated.
您在第3层有6个节点,在第4层有24个节点,因此在第3层的每个节点的平均子代数为 24/6 = 4
.
You have 6 nodes at level 3, 24 nodes at level 4, so the average number of children per node at level 3 is 24/6=4
.
这篇关于如何找到树的分支因子的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!