Android短信总是发送给同一联系人 [英] Android sms is always sent same contact

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本文介绍了Android短信总是发送给同一联系人的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用asynctask将短信发送给多个联系人.但是,当我单击发送"按钮时,短信仅发送到我选择的联系人列表顶部的一个号码.发送的短信数量等于所选联系人列表的大小.我在下面写了短信发送代码.我该如何解决这个问题?

I am trying to send sms to multiple contacts using asynctask. But when i click send button sms is sent to only one number which is top of the my selected contact list. And number of the sent sms is equal to size of the selected contact list. I wrote my sms send code below. How can i fix this problem?

  @Override
  protected final String doInBackground(List<kisiler>... lists) {
      int progress=0;
      final List<contacts> k=lists[0];
      dialog.setMax(k.size());

      while (progress<dialog.getMax()){

            try{

                final String m=k.get(k.size()-1).getName();


                SmsManager smsManager = SmsManager.getDefault();

                publishProgress(String.valueOf(k.size()-1),String.valueOf(k.size()),m,String.valueOf(dialog.getMax()));
                PendingIntent sendPI = PendingIntent.getBroadcast(getActivity(), 0, new Intent(), 0);


                getActivity().registerReceiver(new BroadcastReceiver() {
                    @Override
                    public void onReceive(Context context, Intent intent) {
                        switch (getResultCode()) {
                            case Activity.RESULT_OK:
                          Toast.makeText(getActivity(),getString(R.string.sent_to_sms)+contact.getName(),Toast.LENGTH_LONG).show();

                                break;

                            case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                                Toast.makeText(getActivity(), R.string.failure+kisi2.getIsim(),Toast.LENGTH_LONG).show();

                                break;
                            case SmsManager.RESULT_ERROR_NO_SERVICE:

                                Toast.makeText(getActivity(), R.string.no_service, Toast.LENGTH_LONG).show();
                                break;
                            case SmsManager.RESULT_ERROR_NULL_PDU:
                                break;
                            case SmsManager.RESULT_ERROR_RADIO_OFF:
                                break;
                        }
                    }
                }, new IntentFilter(SENT+m));

                smsManager.sendTextMessage(contact.getNumber(), null, location_information(location), sendPI, null);


            }catch (Exception e){
                e.printStackTrace();
            }

          progress++;

      }

      return "Done";
  }

推荐答案

您总是引用相同的 contact 变量.您需要使用 k 列表和 progress 编号更改它,例如:

You're always refering to the same contact variable. You need to change it with k list and progress number like this:

k.get(progress) // your current contact

将其更改为以下内容:

  @Override
  protected final String doInBackground(List<kisiler>... lists) {
      int progress=0;
      final List<contacts> k=lists[0];
      dialog.setMax(k.size());

  while (progress<dialog.getMax()){

        try{

            final String m=k.get(k.size()-1).getName();


            SmsManager smsManager = SmsManager.getDefault();

            publishProgress(String.valueOf(k.size()-1),String.valueOf(k.size()),m,String.valueOf(dialog.getMax()));
            PendingIntent sendPI = PendingIntent.getBroadcast(getActivity(), 0, new Intent(), 0);


            getActivity().registerReceiver(new BroadcastReceiver() {
                @Override
                public void onReceive(Context context, Intent intent) {
                    switch (getResultCode()) {
                        case Activity.RESULT_OK:
                      Toast.makeText(getActivity(),getString(R.string.sent_to_sms)+k.get(progress),Toast.LENGTH_LONG).show();

                            break;

                        case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                            Toast.makeText(getActivity(), R.string.failure+kisi2.getIsim(),Toast.LENGTH_LONG).show();

                            break;
                        case SmsManager.RESULT_ERROR_NO_SERVICE:

                            Toast.makeText(getActivity(), R.string.no_service, Toast.LENGTH_LONG).show();
                            break;
                        case SmsManager.RESULT_ERROR_NULL_PDU:
                            break;
                        case SmsManager.RESULT_ERROR_RADIO_OFF:
                            break;
                    }
                }
            }, new IntentFilter(SENT+m));

            smsManager.sendTextMessage(k.get(progress).getNumber(), null, location_information(location), sendPI, null);


        }catch (Exception e){
            e.printStackTrace();
        }

      progress++;

  }

这篇关于Android短信总是发送给同一联系人的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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