如何在Android中使用广播接收器停止正在运行的服务 [英] How to stop a running service using broadcast receiver in android

问题描述

我认为我的代码中有一个简单的问题，但我无法弄清楚.我有一个HeaderService，它在某些特定的应用程序上显示气泡弹出窗口.现在我想要的是当用户使用BroadCastReceiver按Home键或Back键时停止该服务.请看一下我的代码，并向我提出一些解决方案.在此先感谢！

这是我的Receiver类

 公共类PopupClosingReceiver扩展了BroadcastReceiver {私人布尔值isMyServiceRunning(Context con){ActivityManager管理器=(ActivityManager)con.getSystemService(Context.ACTIVITY_SERVICE);对于(ActivityManager.RunningServiceInfo服务:manager.getRunningServices(Integer.MAX_VALUE)){如果(HeaderService.class.getName().equals(service.service.getClassName())){返回true；}}返回false；}@Overridepublic void onReceive(Context context，Intent intent){if(isMyServiceRunning(context)){意图serviceIntent =新的Intent(上下文，HeaderService.class);context.stopService(serviceIntent);}} 

AndroidManifest.xml

 < receiver android:name =.PopupClosingReceiver"><意图过滤器>< category android:name ="android.intent.category.HOME"/></intent-filter></receiver> 

解决方案

您可以随时访问该服务，因为该服务已在系统中注册(线程")，等待激活或随时停止./p>

示例:

 公共类Phonecall扩展了BroadcastReceiver {@Overridepublic void onReceive(Context context，Intent intent){Intent song_wweather = new Intent(context，Song_weather.class);//服务类别if(intent.getAction()=="android.intent.action.PHONE_STATE"){TelephonyManager telephonyManager =(TelephonyManager)context.getSystemService(Context.TELEPHONY_SERVICE);PhoneStateListener callStateListener = new PhoneStateListener(){公共无效的onCallStateChanged(int状态，字符串incomingNumber){if(state == TelephonyManager.CALL_STATE_RINGING){context.stopService(song_wweather);}if(state == TelephonyManager.CALL_STATE_IDLE){context.startService(song_wweather);}}};telephonyManager.listen(callStateListener，PhoneStateListener.LISTEN_CALL_STATE);}}} 

I think there is a simple problem in my code but I couldn't figure it out. I have a HeaderService which shows a bubble popup over some particular apps. Now what I want is stop that service when user presses Home key or Back key using BroadCastReceiver. Please take a look at my code and suggest me some solution. Thanks in Advance!!

This is my Receiver class

public class PopupClosingReceiver extends BroadcastReceiver {


private boolean isMyServiceRunning(Context con) {
    ActivityManager manager = (ActivityManager) con.getSystemService(Context.ACTIVITY_SERVICE);
    for (ActivityManager.RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE)) {
        if (HeaderService.class.getName().equals(service.service.getClassName())) {
            return true;
        }
    }
    return false;
}

@Override
public void onReceive(Context context, Intent intent) {

    if(isMyServiceRunning(context)){

        Intent serviceIntent = new Intent(context, HeaderService.class);
        context.stopService(serviceIntent);

    }

}

AndroidManifest.xml

<receiver android:name=".PopupClosingReceiver">
        <intent-filter>
            <category android:name="android.intent.category.HOME"/>
        </intent-filter>
    </receiver>

解决方案

You can access the service at any time because the service is registered in the system ("Thread") wait to be activated or stops at any time.

Example:

 public class Phonecall extends BroadcastReceiver {

   @Override
   public void onReceive(Context context, Intent intent) {

    Intent song_wweather=  new Intent(context,Song_weather.class); //service class
  if(intent.getAction()=="android.intent.action.PHONE_STATE"){

TelephonyManager telephonyManager =
        (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);

PhoneStateListener callStateListener = new PhoneStateListener() {
    public void onCallStateChanged(int state, String incomingNumber)
    {
        if(state==TelephonyManager.CALL_STATE_RINGING){
            context.stopService(song_wweather);
        }


        if(state==TelephonyManager.CALL_STATE_IDLE){
            context.startService(song_wweather);
        }
    }
};
telephonyManager.listen(callStateListener,PhoneStateListener.LISTEN_CALL_STATE);



}}
}

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