是否可以使用Uri.Builder而不使用"//"部分? [英] Is it possible to use Uri.Builder and not have the "//" part?
问题描述
我正在尝试构建 mailto: uri以使用GMail应用发送邮件.我想使用 android.net.Uri.Builder 类执行此操作，但是生成的uri的格式为 mailto://test@example.com ，这使GMail应用程序认为收件人是//test@example.com ，而不只是 test@example.com .
I am trying to build a mailto: uri to send a mail using the GMail app.
I would like to use the android.net.Uri.Builder class to do this, but the resulting uri is in the form mailto://test@example.com, which makes the GMail app think the recipient is //test@example.com, instead of just test@example.com.
我最终这样做:
String uriStr = uriBuilder.toString();
uriStr = uriStr.replaceAll("//", "");
final Uri uri = Uri.parse(uriStr);
但是很明显，这是一个丑陋的骇客...
but clearly, this is an ugly hack...
如果没有//部分，是否无法构建uri?
Is there no way to build the uri without the // part?
推荐答案
这里有几个问题.尽管可以摆脱//部分，但是您将随后松开查询字符串.主要问题是Uri.Builder不允许您使用不透明URI进行查询(不透明URI是绝对URI，其特定于方案的部分不以斜杠字符开头，例如 mailto: URIs).
There are several issues here. While it is possible to get rid of the // part, you will loose the query strings then. The main problem is that Uri.Builder won't let you use queries with opaque URIs (an opaque URI is an absolute URI whose scheme-specific part does not begin with a slash character, like mailto: URIs).
也就是说，您应该使用 uriBuilder.opaquePart()而不是 uriBuilder.authority()，因为后者将您的URI隐式设置为分层，即非透明.这将摆脱//，但是您缺少查询部分，因此无法进行设置，因为对 uriBuilder.appendQueryParameter()的任何调用也
That said, you should use uriBuilder.opaquePart() instead of uriBuilder.authority() because the latter implicitly sets your URI to hierarchical, i.e. non-opaque. This will get rid of the //, but you're lacking the query part then, and you cannot set it, because any call to uriBuilder.appendQueryParameter() also implies a hierarchical URI.
长话短说，要构建一个包含查询的不透明 mailto: URI，您必须使用
Long story short, to construct an opaque mailto: URI that includes queries, you'll have to use
Uri uri = Uri.parse("mailto:receipient@mail.com?subject=title&body=text");
相反.当然，文字 title 和 text 应该是 Uri.encode().
instead. Of course, the literal title and text should be Uri.encode()ed.
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