如何在我的webView外部打开外部链接? [英] how to open external link outside of my webView?
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问题描述
我用php创建了一个网站,并使用webView作为android应用程序打开,我使用网站上的外部链接打开了whatsapp链接.但是,仅当浏览器访问指向我的whatsapp的链接时才起作用,但在我的webView中的链接不起作用.出现网:: ERR_UNKNOWN_URL_SCHEME,如何解决?
MainActivity
package com.example.programmingknowledge.sitehc;
import android.app.Activity;
import android.content.Intent;
import android.net.Uri;
import android.support.v7.app.ActionBarActivity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.webkit.WebSettings;
import android.webkit.WebView;
import android.webkit.WebViewClient;
import com.example.programmingknowledge.easyonlineconverter.R;
public class MainActivity extends Activity {
private WebView myWebView;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
myWebView = (WebView)findViewById(R.id.myWebView);
WebSettings webSettings = myWebView.getSettings();
webSettings.setJavaScriptEnabled(true);
myWebView.loadUrl("http://mysite/index.php#"); //
//myWebView.getSettings().setBuiltInZoomControls(true); //acrescentei zoom
// myWebView.getSettings().setUseWideViewPort(true);
//AQUI BOTEI
//AQUI TIREI
myWebView.setWebViewClient(new WebViewClient(){
public void onReceivedError(WebView view, int errorCode, String description, String failingUrl){
myWebView.loadUrl("file:///android_asset/error.html"); //file:///android_asset/error.html
}
});
}
@Override
public void onBackPressed() {
if(myWebView.canGoBack()) {
myWebView.goBack();
} else {
myWebView.goBack();
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
//noinspection SimplifiableIfStatement
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
}
推荐答案
您必须使用条件为url的自定义webview客户端,该条件检查当前url是否包含匹配的文本
You have to implement custom webview client with condition of url which check current url contains matching text
class MyWebView extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
if (url.contains("whatsapp")) {
Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.whatsapp");
startActivity(launchIntent);
} else {
view.loadUrl(url);
}
return true;
}
}
为此,您必须在URL中添加"whatsapp" 字样才能打开应用程序.
For that, you must have to add "whatsapp" word in your URL for an open app.
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