TypeScript是否具有NaN类型? [英] Does TypeScript have a NaN type?

问题描述

TypeScript是否具有可以为变量声明的NaN类型?

Does TypeScript have a NaN type that I could declare for a variable?

例如，如果我要创建一个像这样的变量:

For example, if I was to create a variable like this:

const number: number = parseInt('123', 10);

我可以将其更改为更准确吗?

Could I change it to be more accurate, like so:

const number: number | NaN = parseInt('123', 10);

基本上我想知道是否可以将变量声明为NaN类型(不是未定义或为null).上面的代码段在TypeScript中不起作用，并且在TypeScript指南的基本类型"或高级类型"中都找不到.

Basically I want to know if I can declare a variable as a NaN type (not undefined or null). The above snippet doesn't work in TypeScript and I can't find it listed in either the Basic or Advanced Types within TypeScript's guides.

推荐答案

Typescript中没有 NaN 类型.在GitHub上有提案，但是没有实现时间表.如果您想在Typescript中看到此功能，请考虑解决该问题.

There is no NaN type in Typescript. There is a proposal for this on GitHub but there is no timeline for implementation. Consider upvoting the issue if you want to see this feature in Typescript.

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