PYSPARK:CX_ORACLE.InterfaceError:不是查询 [英] PYSPARK: CX_ORACLE.InterfaceError: not a query

问题描述

我需要在spark作业中执行更新查询.我正在尝试下面的代码.但面临问题.

i need to perform update query in spark job. i am trying below code. but facing issues.

import cx_Oracle
def query(sql):
    connection = cx_Oracle.connect("username/password@s<url>/db")
    cursor = connection.cursor()
    cursor.execute(sql)
    result = cursor.fetchall()
    return result
v = [10]
rdd = sc.parallelize(v).coalesce(1)
rdd.foreachPartition(lambda x : [query("UPDATE db.tableSET MAPPERS ="+str(i)+" WHERE TABLE_NAME = 'table_name'") for i in x])

当我执行上述过程时，我遇到了以下错误.

when i execute the above process i am getting below error.

cx_Oracle.InterfaceError: not a query

我尝试使用以下代码手动更新.

i tried to update manually using below code.

result = query("<update query>")

当我这样做时，工作会不断执行

when i do this, job is executing continuously

推荐答案

我解决了我的问题.根据卢克的输入.我使用了 fetchall()进行查询.我需要使用 commit().因此更改了代码并检查其工作正常.

I resolved my problem. As per Luke inputs. i used fetchall() which is used for querying. i need to use commit(). so changed the code and checked its working fine.

import cx_Oracle
def query(sql):
    connection = cx_Oracle.connect("username/password@s<url>/db")
    cursor = connection.cursor()
    cursor.execute(sql)
    result = connection.commit()
v = [10]
rdd = sc.parallelize(v).coalesce(1)
rdd.foreachPartition(lambda x : [query("UPDATE db.tableSET MAPPERS ="+str(i)+"WHERE TABLE_NAME = 'table_name'") for i in x])

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