错误使用的Apache2.2配置mod_wsgi的 [英] error in configure mod_wsgi with Apache2.2

问题描述

我是按照这个<一个href=\"http://pradyumnajoshi.word$p$pss.com/2009/06/09/setting-up-mod_wsgi-for-apache-and-django-on-windows/\" rel=\"nofollow\">http://pradyumnajoshi.word$p$pss.com/2009/06/09/setting-up-mod_wsgi-for-apache-and-django-on-windows/

我使用python2.6的，的Apache2.2，Django1.3和Windows XP上的mod_wsgi> 3。现在我已经安装了Apache其正确运行良好。我有添加下面一行在httpd.conf文件： -
的LoadModule wsgi_module模块/ mod_wsgi.so
现在，我重新启动我的Apache服务器，它运行良好。但是，当我在httpd.conf中添加以下行： -

I am using python2.6, Apache2.2, Django1.3 and mod_wsgi>3 on windows xp. now I have installed Apache correctly it is running well. and I have add the following line in httpd.conf file:- LoadModule wsgi_module modules/mod_wsgi.so Now i restart my Apache server It's running well. But when I have add the following lines in httpd.conf:-

WSGIScriptAlias /wsgi "C:/wsgi_app/wsgi_handler.py"

<Directory "C:/wsgi_app">
  AllowOverride None
  Options None
  Order deny,allow
  Allow from all
</Directory>

然后重新启动我的Apache服务器，它给错误的提示请求操作失败

Then restart my Apache server it give error on the prompt "The request operation has failed"

请帮我，我在python新的。

please help me I am new in python.

感谢你。

推荐答案

请确保您有在目录C wsgi_handler.py文件：/ wsgi_app结果
问题可能是你所引用的象征。
着：/wsgi_app/wsgi_handler.py CC：/wsgi_app/wsgi_handler.py和C：/ wsgi_app与C：/ wsgi_app代替。

make sure you have wsgi_handler.py file in the directory C:/wsgi_app.
problem may be the symbol with which you are quoting. replace "C:/wsgi_app/wsgi_handler.py" with "C:/wsgi_app/wsgi_handler.py" and "C:/wsgi_app" with "C:/wsgi_app".

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