从csh脚本更改工作目录 [英] change working directory from csh script

问题描述

我想查找一些正在运行的进程的数据，实际上我正在搜索暂存目录中的相应作业ID.我设法通过以下命令手动执行此操作(假设job-ID为12345):

I want to lookup some data of running processes, actually I'm searching for the scratch directory to a corresponding job-ID. I managed to do that manually by the following commands (assuming the job-ID is 12345):

find ~ -name '12345.out'

这将根据作业查找输出文件:

This finds the output file according to the job:

/home/username/somefolder/12345.out

临时目录被写入该文件夹中名为.scrdir的文件中，因此

The scratch directory is written to a file named .scrdir in that folder, so

cd | cat /home/username/somefolder/.scrdir

把我带到我想要的地方.

brings me where I want.

我现在想将其组合到我的 .cshrc 中的csh脚本或某些别名.

I now want to combine that to a csh script or some alias in my .cshrc.

到目前为止，我的无能

#/bin/csh

set jobfile = `find ~ -name $argv[1].out`
set jobdir = `dirname $jobfile`
set scrdir = `cat $jobdir/.scrdir`
echo $scrdir

其中第一个参数值是作业ID，例如12345该脚本可打印正确的暂存目录，但我希望它在调用脚本后将我的实际工作目录更改为暂存目录.如何在csh脚本中更改工作目录?

where the first argument value is a job-ID, 12345 e.g. This script prints the right scratch directory but I want it to change my actual working directory to the scratch directory after I've called the script. How can I change the working directory from within a csh script?

我也将感谢您提出任何改进问题/-title的建议.

I would also be grateful for any advice to refine the question / -title.

推荐答案

由于csh中没有shell函数，因此我发现的唯一解决方案是使用 source 调用脚本.

Since there are no shell functions in csh, the only solution I found is to call the script with source.

脚本:

#/bin/csh

set jobfile = `find ~ -name $argv[1].out`
set jobdir = `dirname $jobfile`
set scrdir = `cat $jobdir/.scrdir`
cd $scrdir

调用脚本:

source myscript.sh

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