在参数文件中获取当前订阅ID [英] Get current subscription id in parameter file

问题描述

我有这样一个 azuredeploy.parameters.json 文件:

{
  "$schema": "https://schema.management.azure.com/schemas/2015-01-01/deploymentParameters.json#",
  "contentVersion": "1.0.0.0",
  "parameters": {
    "adminLogin": {
      "value": "exampleadmin"
    },
    "adminPassword": {
      "reference": {
        "keyVault": {
          "id": "/subscriptions/[subscription().subscriptionId]/resourceGroups/ARMTemplate/providers/Microsoft.KeyVault/vaults/dev-kv"

        },
        "secretName": "ExamplePassword"
      }
    },
    "sqlServerName": {
      "value": "TestServer"
    }

  }
}

我的目的是提取当前的subscriptionId并将其集成到 id 中.是否可以在参数文件中完成这项工作?

My aim is to extract the current subscriptionId and integrate it into the id. Is it possible in parameter file to do this job?

推荐答案

如果可行，正确的语法应为:

if it works, the correct syntax would be:

"id": "[concat(subscription().id, '/resourceGroups/ARMTemplate/providers/Microsoft.KeyVault/vaults/dev-kv')]"

如果它不起作用，则可以使用嵌套部署将其作为参数传递给嵌套部署并从中返回值，或者只是在嵌套部署中执行您的工作

if it doesnt work you can use a nested deployment to pass it as an argument to a nested deployment and return the value from it or just execute your stuff in a nested deployment

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