将数组拆分为不同大小的块(4、3、3、3、4、3、3、3等) [英] Split array into different size chunks (4, 3, 3, 3, 4, 3, 3, 3, etc)
问题描述
我有一个像这样的数组: [1、2、3、4、5、6、7、9、10]
.我需要将其分成不同大小的块,并使用以下简单模式:4,3,3,3,4,3,3,3,像这样:
I have an array like so: [1, 2, 3, 4, 5, 6, 7, 9, 10]
. I need to chunk it into different size chunks, yet with a simple pattern of: 4, 3, 3, 3, 4, 3, 3, 3 like so:
[
[ // four
1,
2,
3,
4
],
[ // three (1/3)
5,
6,
7
],
[ // three (2/3)
8,
9,
10
],
[ // three (3/3)
11,
12,
13
],
[ // four
14,
15,
16,
17
],
[ // three (1/3)
18,
19,
20
], // and so on..
]
我尝试使用自定义的这段代码:
I have tried with this code I have customized:
const arr; // my array of values
const chuncked = arr.reduce((acc, product, i) => {
if (i % 3) {
return acc;
} else if (!didFourWayReduce) {
didFourWayReduce = true;
fourWayReduces++;
if ((fourWayReduces - 1) % 2) { // only make every second a "4 row"
return [...acc, arr.slice(i, i + 3)];
} else {
return [...acc, arr.slice(i, i + 4)];
}
} else {
didFourWayReduce = false;
return [...acc, arr.slice(i, i + 3)];
}
}, []);
几乎可以正常工作,它期望三分之三的第一个块(1/3)的块的最后一个元素为4.因此,每三个三的第一个块都重复一个键.像这样:
And it works, almost, expect that the first chunk of threes (1/3) have the last element of the chunk with 4. So 1 key is repeated every first chunk of three. Like so:
[
[
1,
2,
3,
4
],
[
4, // this one is repeated, and it shouldn't be
5,
6
]
]
推荐答案
您可以采用两个索引,一个用于数据数组,另一个用于大小.然后以给定的长度对数组进行切片,然后将块推送到块数组.
You could take two indices, one for the data array and one for sizes. Then slice the array with a given length and push the chunk to the chunks array.
继续直到数据结束.
var data = Array.from({ length: 26 }, (_, i) => i + 1),
sizes = [4, 3, 3, 3],
i = 0,
j = 0,
chunks = [];
while (i < data.length) chunks.push(data.slice(i, i += sizes[j++ % sizes.length]));
console.log(chunks);
.as-console-wrapper { max-height: 100% !important; top: 0; }
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