如果名称和值对js中的值为空，则从数组中删除对象 [英] Remove Object From Array if the value is empty in name and value pair js

问题描述

[{name: "mode", value: "1"},{name: "group", value: ""},{name: "from_date", value: ""},{name: "to_date", value: "2018-10-16"},{name: "action", value: "ac_filter_transactions"}

这是我的数组的样子.如果 value 为空，我想从数组中删除名称和值对.

This is how my array looks like. I want to remove the name and value pair from the array if the value is empty.

我尝试了这种解决方案:但这没用

I tried this solution: but this didn't work

formData.map((i) => {
  (i.value == "") ? delete i: "";
});

我知道这是一个简单的问题，但我找不到任何相关的示例来解决此问题.我发现的所有示例和解决方案都是针对此类对象的

I know this is a simple question but I couldn't find any relevant example to solve this problem. All examples and solutions I found was for this type of object

let obj = {"firstname": "XYZ", "lastname": "ABC"}

两个对象之间有什么区别?

What are the difference between both the objects?

推荐答案

您可以使用

You can use Array.prototype.filter and return entries based on a boolean of whether or not the value exists since an empty string is falsy.

a.filter(o => (o.value));

let a = [{name: "mode", value: "1"},{name: "group", value: ""},{name: "from_date", value: ""},{name: "to_date", value: "2018-10-16"},{name: "action", value: "ac_filter_transactions"}];


let result = a.filter(o => (o.value));

console.log(result);

注意:如果您的任何 value 属性也都是虚假的，则它们也不会被选中.为了解决这个问题，您可以简单地使用以下代码重写它:(o.value！==")

Note: If the any of your value properties are also falsy, they won't be picked up either. To get around this you could simply rewrite it using: (o.value !== "")

let a = [{name: "mode", value: "1"},{name: "group", value: ""},{name: "from_date", value: ""},{name: "to_date", value: "2018-10-16"},{name: "action", value: "ac_filter_transactions"}];


let result = a.filter(o => (o.value !== ""));

console.log(result);

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