在PHP中使用时间轴Google Chart API-DataTable初始化 [英] Using timeline google chart api with php - DataTable initialization
问题描述
我正在尝试实施时间表google chart
https://developers.google.com/chart/interactive/docs/gallery/timeline
I am trying to implement the timeline google chart
https://developers.google.com/chart/interactive/docs/gallery/timeline
但是使用日期格式
会在生成图表
时产生一些错误.所有日期均默认设置为 1969年12月31日
.我知道我传递的日期格式错误.我该如何解决.
but using date format
is creating some errors in generating the chart
.
All dates are set default to dec 31 1969
.
I know that I am passing a wrong format of date. How can I fix this.
尝试通过两种方式实施:
tried implementing in two ways :
$table['cols'] = array(
array('id' => 'Role', 'type' => 'string'),
array('id' => 'Name', 'type' => 'string'),
array('id' => 'Start', 'type' => 'date'),
array('id' => 'End', 'type' => 'date')
);
一种方法:
$temp[] = array('v' => (string) $row['FirstName']); /*mysql and mysqli security please ignore */
$temp[] = array('v' => (string) $row['FirstName']);
$temp[] = array('v' => date('D M d Y H:i:s O',$row['HireDate'])); /*tried without date function also*/
$temp[] = array('v' => date('D M d Y H:i:s O',$row['ExpectedEndDate']));
$rows[] = $temp;
其他方式:
$temp[] = $row['FirstName'];
$temp[] = $row['FirstName'];
$temp[] =date('D M d Y H:i:s O',$row['HireDate']);
$temp[] =date('D M d Y H:i:s O',$row['ExpectedEndDate']);
$rows[] = $temp;
,然后将其存储到表中并将其转换为 json
.
and then storing it into table and converting it into json
.
$ table ['rows'] = $ rows;$ jsonTable = json_encode($ table);
使用Google可视化 DataTable
将其存储为javascript变量,如下所示:
storing it as javascript variable using google visualization DataTable
as follows:
var dataTable = new google.visualization.DataTable(<?php echo $jsonTable;?>);
但是由于日期格式冲突(我认为),该图表未输出
But because of date format conflict (I think) the chart is not being outputted
在检查最终生成的输出时,变量会将值存储为:
On inspecting the final generated output the variable is storing the value as :
var dataTable = new google.visualization.DataTable({"cols":[{"id":"Role","type":"string"},{"id":"Name","type":"string"},{"id":"Start","type":"date"},{"id":"End","type":"date"}],"rows":[[{"v":"bob"},{"v":"bob"},{"v":"Wed Dec 31 1969 16:33:28 -0800"},{"v":"Wed Dec 31 1969 16:33:33 -0800"}],[{"v":"alan"},{"v":"alan"},{"v":"Wed Dec 31 1969 16:33:28 -0800"},{"v":"Wed Dec 31 1969 16:33:33 -0800"}]]});
任何人都可以建议如何使其工作.预先感谢.
Can anyone suggest how to make it work. Thanks in advance.
推荐答案
这是您的问题:
$temp[] = array('v' => date('D M d Y H:i:s O',$row['HireDate']));
日期必须以非常特定的字符串格式输入:日期(年,月,日,小时,分钟,秒)"
,其中 month
是该月的索引从零开始, month
之后的所有内容都是可选的( day
的默认值为1,其他所有参数的默认值为0).要以这种格式输入日期,您应该执行以下操作:
Dates must be input in a very specific string-format: "Date(year, month, day, hours, minutes, seconds)"
, where month
is the zero-based index for the month, and everything after month
is optional (defaults are 1 for day
and 0 for everything else). To input your date in this format, you should do something like this:
$date = date('D M d Y H:i:s O',$row['HireDate']));
$year = (int) date_format($date, 'Y');
$month = ((int) date_format($date, 'm')) - 1; // adjust to javascript's 0-indexed months
$day = (int) date_format($date, 'd');
$hours = (int) date_format($date, 'H');
$minutes = (int) date_format($date, 'i');
$seconds = (int) date_format($date, 's');
$temp[] = array('v' => "Date($year, $month, $day, $hours, $minutes, $seconds");
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