使用指针相乘矩阵 [英] Multiplying matrices using pointers

问题描述

嘿，我正在尝试练习用c ++学习指针.因此，我试图将这些数组相乘，并在结果矩阵中获得全0.如果有人可以向我暗示要看的内容或有关导致此的原因的一些建议，那将是惊人的.

Hey guys I am trying practice learning pointers in c++. So I am trying to multiply these arrays and am getting all 0's in my resulting matrix. if anybody could just hint to me what to look at or some advice on what is causing this that would be amazing.

这是代码:

#include <stdio.h>
#include<conio.h>
#include <stdlib.h>
#include <iostream>

/* Routines called. */
int loadMatrixFromFile(char *filename, int *data);
void showMatrix(int *data, int len);
int makeIdent(int matrixB[5][5], int length);
int matrixA[5][5];
int matrixB[5][5];
int matrixC[5][5];
void multiplyMatrices(int matrixA[5][5], int matrixB[5][5],int matrixC[5][5]);

int main(){
    int len, data[1000];
    len = loadMatrixFromFile("Numbers.txt", data);
    showMatrix(data, len);
    makeIdent(matrixB, len);
    multiplyMatrices(matrixA, matrixB, matrixC);
}

int makeIdent(int matrixB[5][5], int len){
    int i,j;
    int *ptr;
    ptr = &matrixB[5][5];
    printf("Matrix B is: \n");
    for(i=0;i<5;i++){
           for(j=0;j<5;j++){
                 if(i==j){
                         *ptr=1;
                         printf("%d ", *ptr);
                 }
                 else{
                     *ptr=0;
                     printf("%d ",*ptr);
                 }
           }
           printf("\n");
     }
    return *ptr;
     printf("\n");
}
int loadMatrixFromFile(char *filename, int *data){
    FILE *in;
    int len;
    int j;
    in = fopen(filename, "r");
    if (in == NULL) {
        printf("Could not find file: %s \n", filename);
    }
    else {
        printf("Reading numbers...\n");
        fscanf(in, "%d", &len);
        printf("reading %d numbers from file %s ....\n", len, filename);
        for(j=0;j<len;j++) {
            fscanf(in, "%d", data + j);
        }
        fclose(in);
    }
    for(int i = 0; i<5; i++){
        for(int j = 0; j < 5; j++){
                matrixA[i][j] = *(data + i*5 + j);
        }
    }
    return len;
}
void showMatrix(int *data, int len){
    int j;
    int count = 0;
    printf("Showing %d numbers from data array....\n", len);
    printf("Matrix A is: \n");
    for(j=0;j<len;j++) {
        printf("%d ", *(data + j));
        count++;
        if(count % 5 == 0){
            printf("\n");
        }
    }
    printf("\n");
}

void multiplyMatrices(int matrixA[5][5], int matrixB[5][5],int matrixC[5][5]){

     int i, n, j;
     int *ptr1, *ptr2, *ptr3;
     ptr1 = &matrixA[5][5];
     ptr2 = &matrixB[5][5];
     ptr3 = &matrixC[5][5];

     printf("\n");
     printf("Matrix A x Matrix B is: \n");
     for(i=0;i<5;i++){
         for(j=0;j<5;j++){
             *ptr3=0;
         }
     }
     for (i = 0; i<5; i++){
            for (j = 0; j<5; j++){
                for(n=0;n<5;n++){
                *ptr3 += (*ptr1**ptr2);
      }
                printf("%d ",*ptr3);
    }
    printf("\n");
  }
}

推荐答案

在 makeIdent 中，您需要在每个元素之后增加 ptr .至初始化 ptr ，您需要将其指向数组中的第一个元素，而不是最后一个元素.

In makeIdent you need to increment ptr after each element. To initialize ptr you need to point it to the first element in the array, not the last element.

int makeIdent(int matrixB[5][5], int len){
    int i,j;
    int *ptr;
    ptr = &matrixB[0][0]; // note the 0 instead of the 5
    printf("Matrix B is: \n");
    for(i=0;i<5;i++){
           for(j=0;j<5;j++){
                 if(i==j){
                         *ptr=1; 
                         printf("%d ", *ptr);

                 }
                 else{
                     *ptr=0;
                     printf("%d ",*ptr);
                 }
                 ptr++; // this is new
           }
           printf("\n");
     }
    return 0;
}

这更接近您想要的multipleMatrices:

This is closer to what you want for multiplyMatrices:

void multiplyMatrices(int matrixA[5][5], int matrixB[5][5],int matrixC[5][5]){

 int i, n, j;
 int *ptr1, *ptr2, *ptr3;
 ptr1 = &matrixA[0][0];
 ptr2 = &matrixB[0][0];
 ptr3 = &matrixC[0][0];

 for (i = 0; i<5; i++) {
     for (j = 0; j<5; j++) {
         *ptr3 = (*ptr1 * *ptr2);
         ptr1++; ptr2++; ptr3++;
     }
 }
}

您可以这样说:

*ptr3++ = *ptr1++ * *ptr2++;

但是我不想混淆这个问题.

But I don't want to confuse the issue.

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