十六进制增量/循环直到FFF [英] Hex increment / loop till FFF

问题描述

我有一个包含十六进制数字的字符串，我想递增该十六进制数字，直到达到最大数字(FFF).我该如何遍历，以便可以获取起始十六进制和FFF之间的每个数字?

I have an string which contains a hexadezimal number and i want to increment that hex number until i reach my max number (FFF). How can i loop through so i can get every number between my start hex and FFF?

我试图将字符串转换为字节数组，但此后被卡住了.

I tried to convert the string in a byte array but got stuck after that.

string stringHex = "7A";
string binaryval = "";
binaryval = Convert.ToString(Convert.ToInt32(stringHex, 16), 2);
int numOfBytes = binaryval.Length / 8;
byte[] bytes = new byte[numOfBytes];

for (int i = 0; i < numOfBytes; ++i)
{
    bytes[i] = Convert.ToByte(binaryval.Substring(8 * i, 8), 2);
}

我需要用它来创建一个显示所有这些数字的表.

I need this to create a table which displays all those numbers.

解决方案:

        string sHex = Convert.ToString(sIPv4.Split(':')[2]);

        for( int intFromHex = int.Parse(sHex, System.Globalization.NumberStyles.HexNumber);intFromHex <= 4095; intFromHex++)//4095 - FFF
        {
            string hexValue = intFromHex.ToString("X");
            //SQL INSERT
        }

推荐答案

您可以将 String 转换为 Int ，将 Int 递增，然后进行转换它返回到 String (Hex)

You can convert String to Int increment the Int and then convert it back to String(Hex)

string stringHex = "7A";

int intFromHex = int.Parse(stringHex , System.Globalization.NumberStyles.HexNumber) + 1;

string hexValue = intFromHex.ToString("X");

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