如何将父代的ID传递给子代的创建视图 [英] How to pass the id of the parent to the create view of a child

问题描述

我是MVC2的新手，我的问题应该很简单.至少我以为是这样，直到在网上找不到任何答案为止，所以我在这里.

I'm new to MVC2 and my question should be pretty basic. At least I thought so until I could'nt find any answer on the web, so here I am.

我有一个父对象Pool，可以有0到多个子问题.

I have a parent object Pool that can have 0 to many children Question.

在"Pool"的详细信息"视图中，除了"Pool"的属性外，到目前为止，我还使用问题"操作列表上的"RenderAction"渲染了他的孩子.

In my Details view of Pool, in addition to the Pool's property, I render his childs using RenderAction on the Question action List, so far, so good.

在问题"的列表"视图中(始终在详细信息"视图中呈现)，我想要一个按钮来启动问题"对象的创建"操作.我的问题是，我不知道如何将详细信息"视图的模型池"对象传递给创建"操作，以便将我的问题"链接到正确的池".

Inside my List view of Question (which is always rendered inside the Details view), I want a button to start the Create action of the Question object. My problem is, I don't know how to pass the Pool object, which is the model of my Details view, to the Create action so that I can link my Question to the right Pool.

是否有一种方法可以通过RenderAction访问包含"视图中的主"模型，如果没有，什么是实现替代方案的最佳方法.

Is there a way to access the "Master" Model inside the "included" view via RenderAction and if not, what's the best way to implement a work around.

谢谢

推荐答案

这是我在MVC中最喜欢的隐藏宝石之一.这将为您提供父模型:

This is one of my favourite hidden gems in MVC.. this will give you the parent model:

<% object parentModel = ViewContext.ParentActionViewContext.ViewData.Model; %>

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