在Odata V4 API中发布DbGeography数据类型 [英] Post DbGeography data type in odata v4 api

问题描述

我从DbGeography数据类型中收到的是位置信息.

What i receive from a DbGeography data type is in Location.

{
    "@odata.context":"http://subdomain.mydomain.me/odata/$metadata#Pois","value":[
      {
          "Id":"d57e6603-5530-4457-b041-6398b7182173","Name":"Demo Home","Address":"Zuidstraat 8 8630 Veurne","Location":{
              "Geography":{
                  "CoordinateSystemId":4326,"WellKnownText":"POINT (51.515574 2.025285)","WellKnownBinary":null
              }
          },"TagId":"ec32e8f3-c0b8-4bcc-af6c-7059b1ef1a65","RouteId":null
      }
    ]
}

我尝试了多个POSTS，但是似乎都没有成功添加DbGeography Point.

I have tried multiple POSTS, but none of them seem to succeed in adding a DbGeography Point.

关于如何执行此操作的任何想法?我尝试添加与返回的内容相同的内容(不起作用)，并使用类型+坐标作为属性(如odata标准中所定义.).

Any thoughts on how to do this? I have tried adding the same as what is returned ( doesn't work) and using type + coordinates as properties ( as defined in the odata standard .

在另一个问题中，我发现了这个从"System.Data.Entity.Spatial.DbGeography"上的"WellKnownValue"获取值时出错，但此解决方案似乎不够.

In another question, i have found this Error getting value from 'WellKnownValue' on 'System.Data.Entity.Spatial.DbGeography , but this solution seems insufficent.

如果我要添加Location:"POINT(lat long)"，我可以使用以下方法来生成数据(但我不知道怎么做)

If i'd add Location : "POINT(lat long)" i could use the following method to generate the data ( but i don't know how)

DbGeography.PointFromText(textValue, 4326)

推荐答案

我将经度坐标发送为纬度，然后像这样在服务器端将纬度转换为DbGeography:

I send the coordinates as longitude, latitude then converts to DbGeography at server side like this:

模型

public class MyModel
{
    [Required]
    public  double Longitude { get; set; }
    [Required]
    public double Latitude { get; set; }
}

控制器

public IHttpActionResult Post(MyModel model)
{
    if (!ModelState.IsValid || model == null)
    {
        // return error
    }

    var coordinates = DbGeography.FromText($"POINT({model.Longitude} {model.Latitude})");

    // save coordinates to database

    return Ok();
}

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