将文件从多个目录复制到单个目标目录 [英] Copying files from multiple directories into a single destination directory

问题描述

有多个目录，其中包含一个具有相同名称的文件:

There are multiple directories which contain a file with the same name:

direct_afaap/file.txt
direct_fgrdw/file.txt
direct_sardf/file.txt
...

现在，我想将它们提取到另一个目录 direct_new 中，并使用其他文件名，例如:

Now I want to extract them to another directory, direct_new and with a different file name such as:

[mylinux~ ]$ ls direct_new/
file_1.txt  file_2.txt  file_3.txt

我该怎么做?

顺便说一句，如果我想将原始目录中的部分名称放入文件名中，例如:

BTW, if I want to put part of the name in original directory into the file name such as:

[mylinux~ ]$ ls direct_new/
file_afaap.txt  file_fgrdw.txt  file_sardf.txt

我该怎么办?

推荐答案

这个小小的BaSH脚本将同时实现两种方式:

This little BaSH script will do it both ways:

#!/bin/sh
#

# counter
i=0

# put your new directory here
# can't be similar to dir_*, otherwise bash will
# expand it too
mkdir newdir

for file in `ls dir_*/*`; do
    # gets only the name of the file, without directory
    fname=`basename $file`
    # gets just the file name, without extension
    name=${fname%.*}
    # gets just the extention
    ext=${fname#*.}

    # get the directory name
    dir=`dirname $file`
    # get the directory suffix
    suffix=${dir#*_}

    # rename the file using counter
    fname_counter="${name}_$((i=$i+1)).$ext"

    # rename the file using dir suffic
    fname_suffix="${name}_$suffix.$ext"

    # copy files using both methods, you pick yours
    cp $file "newdir/$fname_counter"
    cp $file "newdir/$fname_suffix"
done

输出:

$ ls -R
cp.sh*
dir_asdf/
dir_ljklj/
dir_qwvas/
newdir/
out

./dir_asdf:
file.txt

./dir_ljklj:
file.txt

./dir_qwvas:
file.txt

./newdir:
file_1.txt
file_2.txt
file_3.txt
file_asdf.txt
file_ljklj.txt
file_qwvas.txt

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