值对于基数太大(错误令牌为"0925") [英] Value too great for base (error token is "0925")

问题描述

我的bash脚本中具有以下逻辑:

I have the following logic in my bash script:

#!/bin/bash
local_time=$(date +%H%M)

if (( ( local_time > 1430  && local_time < 2230 ) || ( local_time > 0300 && local_time < 0430 ) )); then
 # do something
fi

我时不时地得到标题中指定的错误(在 08xx 上方的任何时间似乎都会触发该错误).

Every now and then, I get the error specified in the title (any time above 08xx appears to trigger the error).

关于如何解决此问题的任何建议?

Any suggestions on how to fix this?

我正在Ubuntu 10.04 LTS上运行

I am running on Ubuntu 10.04 LTS

我按照SiegeX的建议修改了脚本，现在，我得到了错误: [:10#0910:预期为整数表达式.

I modified the script as suggested by SiegeX, and now, I am getting the error: [: 10#0910: integer expression expected.

有帮助吗?

推荐答案

bash 将您的数字视为八进制，因为前导零

bash is treating your numbers as octal because of the leading zero

常数为0的常数是解释为八进制数.一种前导0x或0X表示十六进制.否则，数字采用[base#] n的形式，其中base是小数2到64之间的数字表示-算术基数，并且n是该基数中的数字.如果base#是省略，则使用10为底.

Constants with a leading 0 are interpreted as octal numbers. A leading 0x or 0X denotes hexadecimal. Otherwise, numbers take the form [base#]n, where base is a decimal number between 2 and 64 represent- ing the arithmetic base, and n is a number in that base. If base# is omitted, then base 10 is used.

要解决此问题，请指定以10为底的前缀

To fix it, specify the base-10 prefix

#!/bin/bash
local_time="10#$(date +%H%M)"

if (( ( local_time > 1430  && local_time < 2230 ) || ( local_time > 0300 && local_time < 0430 ) )); then
 # do something
fi

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