如何将$ PATH的内容分成不同的行? [英] How to split the contents of `$PATH` into distinct lines?

问题描述

假设 echo $ PATH 产生/first/dir:/second/dir:/third/dir .

问题:一个如何一次回显一个目录中 $ PATH 的内容，如:

Question: How does one echo the contents of $PATH one directory at a time as in:

$ newcommand $PATH
/first/dir
/second/dir
/third/dir

最好，我试图找出如何使用 for 循环来执行此操作，该循环为 $中的目录的每个实例发出一个 echo 实例PATH .

Preferably, I'm trying to figure out how to do this with a for loop that issues one instance of echo per instance of a directory in $PATH.

推荐答案

echo "$PATH" | tr ':' '\n'

应该做到这一点.这将简单地使用 echo"$ PATH" 的输出，并用换行符分隔符替换任何冒号.

Should do the trick. This will simply take the output of echo "$PATH" and replaces any colon with a newline delimiter.

请注意， $ PATH 周围的引号可防止在 $ PATH 的输出中多个连续空格的折叠，同时仍输出变量的内容.

Note that the quotation marks around $PATH prevents the collapsing of multiple successive spaces in the output of $PATH while still outputting the content of the variable.

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