如何在Bash中进行浮点比较? [英] How can I do float comparison in Bash?

问题描述

lock_percent=$(echo "scale = 5; $value2*100/$value1" | bc)
value=`echo "$lock_percent" | bc`

    if [[ "$value" > "$8" ]]; then
       echo "Lock Percentage:$value percentage State Critical"
       exit $STATE_CRITICAL
    fi

我无法与此进行浮点比较.我要去哪里错了?

I am not able to perform a float comparison with this. Where am I going wrong?

推荐答案

Bash本身不能使用float.在这种情况下，您可以乘以10或100(以此类推)，然后得到可以比较的整数值.或者，您可以使用 bc 比较并返回值:

Bash itself can't use float. In this case maybe you can multiply by 10 or 100 (etc.) and get integer value which you can compare. Or, you can use bc comparison and return value:

echo "10.2>10.1" | bc

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