如何检查字符串是否包含特殊字符(！@#$％^& *()_ +) [英] How to check if a string contains a special character (!@#$%^&*()_+)

问题描述

我想知道什么是检查字符串是否为

I was wondering what would be the best way to check if a string as

$str 

包含以下任何字符

!@#$%^&*()_+

我曾考虑使用ASCII值，但是对于确切的实现方式却有些困惑.

I thought of using ASCII values but was a little confused on exactly how that would be implemented.

或者，如果有一种更简单的方法可以根据值检查字符串.

Or if there is a simpler way to just check the string against the values.

推荐答案

将其与全局匹配.您只需要转义外壳否则认为特殊的字符:

Match it against a glob. You just have to escape the characters that the shell otherwise considers special:

#!/bin/bash
str='some text with @ in it'
if [[ $str == *['!'@#\$%^\&*()_+]* ]]
then
  echo "It contains one of those"
fi

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