在Bash中用逗号分隔的字符串 [英] Split a comma separated strings in Bash
本文介绍了在Bash中用逗号分隔的字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的文件中包含20k + IP:
I have this file with 20k+ IPs inside:
104.20.15.220,104.20.61.219,104.20.62.219,104.20.73.221,104.20.74.221,104.20.14.220
104.20.15.220,104.20.73.221,104.20.74.221,104.25.195.107,104.25.196.107,104.20.14.220
91.215.154.209
...
问题是如何在每个字符串上拆分成单个IP:
The question is how to split in into single IPs on each string:
104.20.15.220
104.20.61.219
推荐答案
只需使用以下任一命令用新行替换逗号:
Just replace a comma with a new line with either of these commands:
tr ',' '\n' < file
sed 's/,/\n/g' file
perl 's/,/\n/g' file
awk 'gsub(/,/,"\n")' file
...或将每个文本块匹配到逗号或行尾:
... or match every block of text up to a comma or the end of line:
grep -oP '.*?(?=,|$)' file
...或遍历字段并打印它们:
... or loop through the fields and print them:
awk -F, '{for(i=1;i<=NF;i++) print $i}' file
...或将记录分隔符设置为逗号,然后让 awk
完成所有工作:
... or set the record separator to the comma and let awk
do all the work:
awk -v RS=, '1' file
awk 1 RS=, file
...或匹配IP,您可以使用匹配IPv4地址:
... or match the IPs, you can use the regex from Matching IPv4 Addresses:
grep -oE '((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)' file
他们都返回:
They all return:
104.20.15.220
104.20.61.219
104.20.62.219
104.20.73.221
...
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