sed-替换多个连续的行匹配模式 [英] sed - replace several consecutive lines matching pattern

问题描述

我正在尝试用文本替换文件中的两个连续行.例如:
testfile.rb

I am trying to replace two consecutive lines in a file with my text. For example:
testfile.rb

class Test
  def procedure
    nil
  end
end

我正在努力实现这一目标:
testfile.rb

I am trying to achieve this:
testfile.rb

class Test
  def procedure
    nil
  finish
finish

所以我需要替换最后两行，但这行不通:

So I need to replace last 2 lines but this doesn't work:

sed -i 's/^\s\send\nend/  finish\nfinish/' testfile.rb

我知道它会失败，因为替换是逐行进行的.但是我该怎么办呢?

I understand that it fails because replacement is line by line. But how can I do it?

推荐答案

sed '/end$/N;//s/end/finish/g' testfile.rb

结果

class Test
  def procedure
    nil
  finish
finish

• 我们只想在两行都包含 end 的情况下查看它们，所以仅当第一行以 end
结尾时才在第二行中读取
• 用完成
替换 end
• we want to look at a pair of lines only when they might both contain end, so only read in second line when first line ends with end
• replace end with finish

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