在bash脚本中运行ssh-agent [英] Running ssh-agent in bash script

问题描述

我创建了ssh-start.sh文件，其中包含:

I have created file ssh-start.sh which contains:

eval "$(ssh-agent -s)"
ssh-add ~/.ssh/id_rsa

我正在运行它并输出:

Agent pid 1234
Identity added: ~/.ssh/id_rsa (~/.ssh/id_rsa)

但是我跑步时

ssh-add -l

我得到了:

Could not open a connection to your authentication agent.

我在做什么错以及如何解决?

What am I doing wrong and how to fix that?

(当我直接在终端中运行ssh-start.sh文件中的命令时，它工作正常)

(when I run commands from ssh-start.sh file directly in terminal it works fine)

推荐答案

ssh 命令需要知道如何与 ssh-agent 对话.他们从 SSH_AUTH_SOCK 环境变量知道这一点.

ssh command needs to know how to talk to the ssh-agent. They know that from the SSH_AUTH_SOCK environment variable.

[gc@slave4 ~]$ ssh-agent -s
SSH_AUTH_SOCK=/tmp/ssh-ln4RuPajkE2A/agent.11091; export SSH_AUTH_SOCK;
SSH_AGENT_PID=11092; export SSH_AGENT_PID;
echo Agent pid 11092;

如果在脚本之后运行 ssh-add -l <​​/code> ，则 ssh 和 ssh-add 都不会能够看到已设置 SSH_AUTH_SOCK 环境变量.因此，将所有命令作为脚本的一部分运行，或者在命令提示符下运行所有​​命令.

If you run ssh-add -l after the script, neither ssh nor ssh-add will be able to see that the SSH_AUTH_SOCK environment variable is set. So run all commands as part of a script or all from the command prompt.

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