用父".."规范化路径bash脚本中间的目录 [英] Normalize paths with parent ".." directories in the middle in bash script

问题描述

我有一个存储在bash变量中的路径列表，例如以下内容

I have a list of paths stored in a bash variable, such as the following

>>> MY_PATHS= ../Some/Path/ ../Some/Other/../Path/

我想要一个唯一的相对路径列表，但是由于第二个路径中使用了".."父目录，所以我不能仅将它们通过管道传递给 uniq .

I'd like to have a list of unique relative paths, but due to the ".." parent directory used in the second path I can't just pipe these to uniq.

是否存在标准化目录路径的标准Linux方法?

我想要的结果是这样

>>> echo $MY_UNIQUE_PATHS
../Some/Path/

推荐答案

似乎python的

It seems python's relpath can do it all for me...

#!/usr/bin/python
import sys, os, pipes
paths = sys.argv[1:]                 #arguments are a list of paths
paths = map(os.path.relpath, paths)  #"normalize" and convert to a relative path
paths = set(paths)                   #remove duplicates
paths = map(pipes.quote, paths)      #for filenames with spaces etc
print " ".join(paths)                #print result

示例:

>>> normpath ../Some/Path/ ../Some/Other/../Path/
../Some/Path
>>> normpath ../Some/Path/ ../Some/Other/../Different\ Path/
'../Some/Different Path' ../Some/Path

如果需要绝对路径，请将 relpath 替换为 绝对路径 .

If absolute paths are wanted, replace relpath with abspath.

谢谢@devnull！

Thanks, @devnull!

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