从bs4.element.Tag获取项目 [英] Get item from bs4.element.Tag

问题描述

我有一个类型为bs4.element.Tag的元素

I have element with type bs4.element.Tag

<a class="nav-link match-link-stats" href="/football/matches/match867851_Kalteng_Putra-Arema-online/" title="Stat"><i class="icon-match-link"></i></a>

我想从该元素中获取"/football/matches/match867851_Kalteng_Putra-Arema-online/".怎么做?

And I want to get "/football/matches/match867851_Kalteng_Putra-Arema-online/" from this element. How to do it?

推荐答案

此答案假定您已经具有 Tag 元素作为对象.如果没有，请使用KunduK的答案.

This answer assumes you already have the Tag element as an object. If not, use KunduK's answer.

您可以使用 tag.get('href')或 tag ['href'] :

>>> tag.get('href')
'/football/matches/match867851_Kalteng_Putra-Arema-online/'
>>> tag['href']
'/football/matches/match867851_Kalteng_Putra-Arema-online/'

区别在于，如果属性不存在， tag.get('href')将返回None，而 tag ['href'] 将引发一个在这种情况下为 KeyError .这与 dict 中的行为相同.

The difference is that tag.get('href') will return None if the attribute doesn't exist, while tag['href'] will raise a KeyError in that case. That's the same behavior as in a dict.

完整示例:

>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup('<a class="nav-link match-link-stats" href="/football/matches/match867851_Kalteng_Putra-Arema-online/" title="Stat"><i class="icon-match-link"></i></a>')
>>> tag = soup.find('a')
>>> type(tag)
<class 'bs4.element.Tag'>
>>> tag.get('href')
'/football/matches/match867851_Kalteng_Putra-Arema-online/'
>>> tag['href']
'/football/matches/match867851_Kalteng_Putra-Arema-online/'

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