BeautifulSoup4:选择属性不等于x的元素 [英] BeautifulSoup4: select elements where attributes are not equal to x

问题描述

我想做这样的事情:

soup.find_all('td', attrs!={"class":"foo"})

我想找到所有没有foo类的td.
显然上述方法不起作用，怎么办?

I want to find all td that do not have the class of foo.
Obviously the above doesn't work, what does?

推荐答案

BeautifulSoup 确实使汤"漂亮且易于使用.

BeautifulSoup really makes the "soup" beautiful and easy to work with.

您可以在属性值中传递函数:

soup.find_all('td', class_=lambda x: x != 'foo')

演示:

>>> from bs4 import BeautifulSoup
>>> data = """
... <tr>
...     <td>1</td>
...     <td class="foo">2</td>
...     <td class="bar">3</td>
... </tr>
... """
>>> soup = BeautifulSoup(data)
>>> for element in soup.find_all('td', class_=lambda x: x != 'foo'):
...     print element.text
... 
1
3

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