在Twitter API中使用since_id和max_id [英] using since_id and max_id in Twitter API

问题描述

我希望我对此有所考虑，并且有一个明显的解决方案.

I hope I'm overthinking this and there's an obvious solution.

从API(获取状态/用户时间轴)

From the API (GET statuses/user_timeline)

max_id-返回ID小于(即早于)或等于指定ID的结果.

max_id - Returns results with an ID less than (that is, older than) or equal to the specified ID.

或等于" 表示它将包含ID为我的max_id参数发送的tweet.

"or equal to" means it will include the tweet with ID that I sent as my max_id parameter.

-

我的问题是:如果我存储了我最早的tweet的ID(来自上一个请求)，如何从该ID中减去1，以排除它在下一个请求中返回?

My question is this: if I store the id of my oldest tweet (from a previous request), how can I subtract 1 from this id to exclude it from being returned in my next request?

显而易见的解决方案是执行类似'& max_id ='+ lastID-1的操作，但对于此类数学运算，twitter ID很大，而javascript将结果四舍五入.

The obvious solution would be to do something like this '&max_id='+lastID-1, but twitter IDs are way to large for such math operations and javascript rounds off the results.

有关雪花更新的详细信息: https://dev.twitter.com/docs/twitter-ids-json和雪花

Details about the snowflake update: https://dev.twitter.com/docs/twitter-ids-json-and-snowflake

可能的解决方案:

已经提到我可以使用BigInteger Javascript库: http://silentmatt.com/biginteger/，但在我看来，这对于诸如小任务来说是多余的.

It has been mentioned that I can use the BigInteger Javascript Library: http://silentmatt.com/biginteger/, but in my opinion this is redundant for such as small task.

我是否必须对字符串(id_str)使用递归并将其递增或递减1?我不喜欢使用hack来处理那些应该有效的小细节.

Do I have to use recursion on the string (id_str) and increment or decrement it by one? I hate to use a hack for such as small detail that should just work.

-

如果您遇到此问题，请分享您的解决方案.

If you've had this problem please share your solution.

谢谢！

推荐答案

我遇到了同样的问题，最后通过从最后一位减去1来解决了这个问题，然后考虑了从1减去1时的情况.通过递归0.

I ran into this same problem, and ended up solving it by subtracting 1 from the last digit, and then accounting for the scenario when we're subtracting 1 from 0 via recursion.

function decrementHugeNumberBy1(n) {
    // make sure s is a string, as we can't do math on numbers over a certain size
    n = n.toString();
    var allButLast = n.substr(0, n.length - 1);
    var lastNumber = n.substr(n.length - 1);

    if (lastNumber === "0") {
        return decrementHugeNumberBy1(allButLast) + "9";
    }
    else {      
        var finalResult = allButLast + (parseInt(lastNumber, 10) - 1).toString();
        return trimLeft(finalResult, "0");
    }
}

function trimLeft(s, c) {
    var i = 0;
    while (i < s.length && s[i] === c) {
        i++;
    }

    return s.substring(i);
}

这篇关于在Twitter API中使用since_id和max_id的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！