将十六进制转换为二进制(大值) [英] Convert Hexadecimal to Binary (large values)

问题描述

-(NSString *)toBinary:(NSUInteger)input
{
    if (input == 1 || input == 0)
        return [NSString stringWithFormat:@"%u", input];
    return [NSString stringWithFormat:@"%@%u", [self toBinary:input / 2], input % 2];
}

NSString *hex = txtHexInput.text;
NSUInteger hexAsInt;
[[NSScanner scannerWithString:hex] scanHexInt:&hexAsInt];
NSString *binary = [NSString stringWithFormat:@"%@", [self toBinary:hexAsInt]];
txtBinaryInput.text = binary;

上面的代码非常有效……直到您需要超过32位为止.对于大于32位值的任何将十六进制转换为二进制的指针?谢谢.

The above code works great... that is until you need to exceed 32 bits. Any pointers to converting hex to binary for larger than 32 bit values? Thank you.

推荐答案

您可以使用 uint64_t 或 unsigned long long 获得64位.

You can get 64 bits using uint64_t or unsigned long long.

-(NSString *)toBinary:(unsigned long long)input
{
    if (input == 1 || input == 0)
        return [NSString stringWithFormat:@"%llu", input];
    return [NSString stringWithFormat:@"%@%llu", [self toBinary:input / 2], input % 2];
}

NSString *hex = txtHexInput.text;
unsigned long long hexAsULL;
[[NSScanner scannerWithString:hex] scanHexLongLong:&hexAsULL];
NSString *binary = [NSString stringWithFormat:@"%@", [self toBinary:hexAsULL]];
txtBinaryInput.text = binary;

这将为您提供0到18,446,744,073,709,551,615(十进制)之间的数字

This will give you numbers from 0 to 18,446,744,073,709,551,615 (decimal)

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