java.util.regex.PatternSyntaxException [英] java.util.regex.PatternSyntaxException
问题描述
我修改了BluetoothChat代码以从微控制器接收串行数据到我的android手机.当我运行以下代码片段时,它给出了java.util.regex.PatternSyntaxException.错误到底是什么?为什么会发生这种异常?
I have modified the BluetoothChat code to receive serial data from a micro-controller to my android phone. When I run the following code snippet it gives java.util.regex.PatternSyntaxException. What exactly is the error? Why is this exception happening?
BluetoothChat.java
BluetoothChat.java
// The Handler that gets information back from the BluetoothChatService
private final Handler mHandler = new Handler() {
@Override
public void handleMessage(Message msg) {
switch (msg.what) {
case MESSAGE_WRITE:
byte[] writeBuf = (byte[]) msg.obj;
// construct a string from the buffer
String writeMessage = new String(writeBuf);
mConversationArrayAdapter.add(writeMessage);
break;
case MESSAGE_READ:
byte[] readBuf = (byte[]) msg.obj;
// construct a string from the valid bytes in the buffer
String readMessage = new String(readBuf, 0, msg.arg1);
if(readMessage.matches("*"))
{
mConversationArrayAdapter.add("Left");
}
else
{mConversationArrayAdapter.add(readMessage);}
}
登录猫:
09-15 13:54:32.070: E/AndroidRuntime(21931): FATAL EXCEPTION: main
09-15 13:54:32.070: E/AndroidRuntime(21931): java.util.regex.PatternSyntaxException: Syntax error in regexp
pattern near index 1:
09-15 13:54:32.070: E/AndroidRuntime(21931): *
09-15 13:54:32.070: E/AndroidRuntime(21931): ^
09-15 13:54:32.070: E/AndroidRuntime(21931): at java.util.regex.Pattern.compileImpl(Native Method)
09-15 13:54:32.070: E/AndroidRuntime(21931): at java.util.regex.Pattern.compile(Pattern.java:400)
09-15 13:54:32.070: E/AndroidRuntime(21931): at java.util.regex.Pattern.<init>(Pattern.java:383)
09-15 13:54:32.070: E/AndroidRuntime(21931): at java.util.regex.Pattern.matches(Pattern.java:413)
09-15 13:54:32.070: E/AndroidRuntime(21931): at java.lang.String.matches(String.java:1765) 09-15 13:54:32.070:
E/AndroidRuntime(21931): at
com.example.footforthought.Sixth$2.handleMessage(Sixth.java:289)
09-15 13:54:32.070: E/AndroidRuntime(21931): at android.os.Handler.dispatchMessage(Handler.java:99)
09-15 13:54:32.070: E/AndroidRuntime(21931): at android.os.Looper.loop(Looper.java:137)
09-15 13:54:32.070: E/AndroidRuntime(21931): at android.app.ActivityThread.main(ActivityThread.java:4517)
09-15 13:54:32.070: E/AndroidRuntime(21931): at java.lang.reflect.Method.invokeNative(Native Method)
09-15 13:54:32.070: E/AndroidRuntime(21931): at java.lang.reflect.Method.invoke(Method.java:511)
09-15 13:54:32.070: E/AndroidRuntime(21931): at .android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:993)
09-15 13:54:32.070: E/AndroidRuntime(21931): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:760)
09-15 13:54:32.070: E/AndroidRuntime(21931): at dalvik.system.NativeStart.main(Native Method)
推荐答案
matches()
使用正则表达式(regex)来匹配输入,而 *
是正则表达式元字符,表示零个或多个前一个令牌.由于没有先前的标记,因此是语法错误.
matches()
uses regular expressions (regex) for matching the input and *
is a regex metacharacter, meaning zero or more of the previous token. Since there's no previous token, it's a syntax error.
如果您想直接匹配 *
,请使用反斜杠对其进行转义:
If you want to match *
literally, escape it with backslash:
readMessage.matches("\\*")
或使用一些不使用正则表达式的字符串匹配函数,例如 equals()
.
or use some of the string-matching functions such as equals()
that don't use a regular expression.
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