从Android中的另一个类访问按钮 [英] Access a button from another class in android
本文介绍了从Android中的另一个类访问按钮的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我知道在SO中也有类似的问题,但很遗憾,这些问题都没有达到我的目的.
I know there are similar questions asked before in SO, but sorry to say that, none of them are serving my purpose.
我在一个活动类中有一个按钮,我想在另一个类中提供其功能.
I have a button in an activity class, and I want to give its functionality in another class.
以下是我的HomeActivity代码:
Below is my HomeActivity code:
// Tile Button
tileButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
TileButton tileView = new TileButton();
tileView.tile();
}
});
这是TileButton.java类代码:
And here is TileButton.java class code:
public class TileButton {
HomeActivity homeActivity = new HomeActivity();
View view = homeActivity.hometabView;
public void tile(){
if(view.isShown()){
view.setVisibility(View.INVISIBLE);
}else{
view.setVisibility(View.VISIBLE);
}
}
}
现在,当我按下平铺按钮时,将引发Null Pointer Exception.下面是LogCat条目.
Now when I press the tile button, a Null Pointer Exception is thrown. Below is the LogCat entry.
10-04 10:32:07.833: E/AndroidRuntime(5330): java.lang.NullPointerException
如何解决此问题?请帮助
How do I solve this problem? Please help
推荐答案
更改:
public class TileButton {
public void tile(View view){
if(view.isShown()){
view.setVisibility(View.INVISIBLE);
}else{
view.setVisibility(View.VISIBLE);
}
}
}
// Tile Button
tileButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
TileButton tileView = new TileButton();
tileView.tile(v);// you can pass any view from here
}
});
这篇关于从Android中的另一个类访问按钮的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文