确保用户输入与我的程序生成的字符匹配 [英] Making sure a user's input matches characters generated by my program

问题描述

这是用于作业

我正在编写一个拼字游戏的简化游戏，在该游戏中，我的程序随机生成字符，然后用户将尝试从这些生成的字符中创建一个单词，然后获得分数.我遇到的问题是确保用户实际上正在使用提供的字符.我不知道如何解决此问题.我不需要任何代码，但是提示将不胜感激，甚至链接也可以作为起点.谢谢你的帮助！

I'm programming a simplified game of scrabble where I have my program randomly generate characters then the user would try and create a word from those generated characters, then get a score afterwards. The issue I'm having is making sure the user is actually using the characters provided. I have no clue on how to approach this problem. I don't need any code but hints would be appreciated or even links for a point to start at. Thanks for any help!

编辑-我的程序大约有一半[创建字母集的部分]

EDIT - About half my program [The part that creates the letter set]

 void generate_letter_set(int letter_set[] , int size_let , int num_let)  
 {
  int arr[N];

const char let[] = 
{'K','J','X','Q','Z','B','C','M','P','F','H','V','W','Y','G','L','S','U','D','N','R','T','O','A','I','E'};

const int freq[] = 
{ 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 4, 4, 4, 4, 6, 6, 6, 8, 9, 9, 12 };

int score[] =
{ 5, 8, 8, 10, 10, 3, 3, 3, 3, 4, 4, 4, 4, 4, 2, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1};

        int index = 0; 
    for(int i = 0 ; i < 26 ; i++) {
for(int f = 0 ; f < freq[i]; f++) {
        arr[index++] = let[i];  //All the 96 letters are stored in let[i]
            //printf("%c " , let[i]);  // Created the letter bank for all the letters 

 } 
}       int letter;
        printf("Your letters are: ");
    for(int l = 0; l < 7; l++){
            letter = rand() % 97; 
        printf("%c ", arr[letter]);


                                }   
}

推荐答案

有很多方法可以在数组中搜索某些字符.您需要的基础是一个非常简单的搜索功能.

There are a lot of different ways to search an array for certain characters. The basis of what you need is a very simple search function.

一个简单的解决方案是使用两个嵌套的 for 循环.假设let []是您要检查的干草堆"，而单词是您的用户输入:

One simple solution would be to use two nested for loops. Assuming let[] is your 'haystack' to check and word is your user input:

// Check each letter of word[]...
for (int ii = 0; ii <= lengthOfUserInput; ii++)
{
    char characterToValidate = word[ii];
    // ... for not existing in let[]
    for (int jj = 0; jj <= lengthOfStringOfValues; jj++)
    {
        if (characterToValidate != let[jj])
    }
}

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