通过条件化另一个对象属性来访问对象数组中的对象值 [英] Accesing object value in array of objects by conditioning another object property

问题描述

这可行，但问题是我可以在此 find方法中一次保存 naziv.value 在 var naziv 中吗不必声明另一个变量?

This works, but question is can I save the naziv.value in var naziv in one go, inside this find method so I don't have to declare another variable?

var naziv = obj.find(c => c.name === "naziv");
console.log(naziv.value)

当前输出是应该通过 console.log(naziv.value)进行的 test ，我想只是 console.log(naziv)

Current output is as it should be test by console.log(naziv.value), I would like to be just console.log(naziv)

var obj = [{
    name: "naziv",
    value: "test"
  },
  {
    name: "zzz",
    value: "xxx"
  }
]

var naziv = obj.find(c => c.name === "naziv");
console.log(naziv.value)

如果名称相同，还可以创建一个数组或值，例如:

And also to make an array or values if name is the same, example:

var obj = [{
    name: "naziv",
    value: "test"
  },
  {
    name: "zzz",
    value: "xxx"
  },
  {
    name: "Telefon[]",
    value: "tel1"
  }, {
    name: "Telefon[]",
    value: "tel2"
  }
]

var naziv = obj.find(c => c.name === "Telefon[]");
console.log(naziv.value)

应为: [tel1，tel2]

推荐答案

如果您希望多个值作为数组，这可能是其中一种方法

If you want multiple values to be as an array, this can be one of the ways

var obj = [{name:"naziv",value:"test"},{name:"zzz",value:"xxx"},{name:"Telefon[]",value:"tel1"},{name:"Telefon[]",value:"tel2"}]

var naziv = obj.filter(c => c.name === "Telefon[]").map(res => res.value);
console.log(naziv)

同样，如果该值本身是预期的输出，并且如果仅期望单个值，则使用以下方法之一.在这里，我使用了 可选链接

Likewise, if the value is itself is the intended output and if only single value is expected then below is one of the ways. Here, I have used Optional Chaining

var obj = [{name:"naziv",value:"test"},{name:"zzz",value:"xxx"},{name:"Telefon[]",value:"tel1"}]

var naziv = obj.find(c => c.name === "Telefon[]")?.value;
console.log(naziv)

如果您需要此代码来运行某些较旧版本的浏览器，并且不支持 Optional Chaining ，那么下面是另一种方式

There could be a chance if you need this code to run some older versions of the browsers and there's no support for Optional Chaining then below is yet another way

var obj = [{name: "naziv",value: "test"},{name: "zzz",value: "xxx"},{name: "Telefon[]",value: "tel1"}]

var naziv = (obj.find(c => c.name === "Telefon[]") || {}).value;
console.log(naziv)

var notFound = (obj.find(c => c.name === "not_found") || {}).value;
console.log(notFound);

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