如何将2个数组与一个对象合并? [英] How to merge 2 arrays with objects in one?

问题描述

我有2个数组:

1. [{名称:'test'，姓氏:'test'，性别:'f'}，{名称:'test1'，姓氏:'test1'，性别:'f'}，{name:'test2'，姓氏:'test2'，性别:'m'}]

[{{名称:'test21'，姓氏:'test21'，性别:'f'}，{name:'test1'，姓氏:'test1'，性别:'f'}，{name:'test2'，姓氏:'test2'，性别:'m'}，{name:'test22'，姓氏:'test22'，性别:'m'}]

如何将它们与唯一对象(用于唯一检查名称")合并到一个数组中?

How to merge these in one array with unique objects (for unique check 'name')?

推荐答案

filter 和 find 的组合将起作用

var a = [{name:'test', lastname: 'test', gender:'f'},{name:'test1', lastname: 'test1', gender:'f'},{name:'test2', lastname: 'test2', gender:'m'}];

var b = [{name:'test21', lastname: 'test21', gender:'f'},{name:'test1', lastname: 'test1', gender:'f'},{name:'test2', lastname: 'test2', gender:'m'},{name:'test22', lastname: 'test22', gender:'m'}];

var c = a.filter(a => b.find(b => b.name === a.name) === undefined).concat(b);

console.table(c);

您还可以制作一个通用的 uniqueByKey 函数

You could also make a generic uniqueByKey function

var uniqueByKey = (key, xs)=>
  xs.reduce((ys,x)=>
    ys.find(y=> y[key] === x[key]) === undefined
      ? ys.concat([x])
      : ys,
    []);

var a = [{name:'test', lastname: 'test', gender:'f'},{name:'test1', lastname: 'test1', gender:'f'},{name:'test2', lastname: 'test2', gender:'m'}];

var b = [{name:'test21', lastname: 'test21', gender:'f'},{name:'test1', lastname: 'test1', gender:'f'},{name:'test2', lastname: 'test2', gender:'m'},{name:'test22', lastname: 'test22', gender:'m'}];

var c = uniqueByKey('name', a.concat(b));

console.table(c);

如果要处理特别大的数据集，则使用 Set 缓存而不是 Array.prototype.find 可能更好.

If you're dealing with particularly large datasets, using a Set cache instead of Array.prototype.find might be better.

var uniqueByKey = (key, xs)=>
  xs.reduce(([set, ys], x)=>
    set.has(x[key])
      ? [set, ys]
      : [set.add(x[key]), ys.concat([x])]
    , [new Set, []]
  ) [1];

var a = [{name:'test', lastname: 'test', gender:'f'},{name:'test1', lastname: 'test1', gender:'f'},{name:'test2', lastname: 'test2', gender:'m'}];

var b = [{name:'test21', lastname: 'test21', gender:'f'},{name:'test1', lastname: 'test1', gender:'f'},{name:'test2', lastname: 'test2', gender:'m'},{name:'test22', lastname: 'test22', gender:'m'}];

var c = uniqueByKey('name', a.concat(b));

console.table(c);

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