寻找一种构造多维多层关联数组的方法 [英] Searching for a way to construct a multidimensional, multilayered, associative Array
问题描述
因此,在遍历字符串并将其chars作为索引数组插入多维关联数组时遇到麻烦.所以基本上是一维多维数组中的一维多维数组.这有点麻烦,因为我无法手动完成.我需要一种自动化的方法来处理一堆字符串.下面的示例将对它进行一些解释,我认为:
So i am running into trouble while iterating through a string and inserting it's chars as index-arrays into a multidimensional,associative array. So basically a bunch of multidimensional arrays in multidimensional arrays in multidimensional arrays..... That is a bit troublesome as i cant do it by hand. I need an automated way to do this with a bunch of strings. The following example will explain it a bit better i think:
//string i want to enter
$string = 'ADAM';
//array i want to end up with
$result = array
(
'A'=> array
(
'D'=>array
(
'A'=>array
(
'M'=>array
(
'result'=>'ADAM'
)
)
)
)
)
我最初的方法是使用if-conditions将第一个Char作为数组插入到主数组中,例如:
my initial approach was just using if-conditions to insert the first Char as Array into the main-array like:
for($i = 0; $i < strlen($string); $i++){
if($i == 0){
$array1[$word[$i]] = array();
}
}
效果很好.但是后来我遇到了问题:如何跟踪数组中的当前点?在执行if-check之后,我将寻求一个else语句,该语句在$ i大于0时起作用.但是,如果我想插入数组的下一个维,在这种情况下为'D',则我需要选择$ array1 ['A'],接下来,我将需要$ array1 ['A'] ['D']等.我无法找到一种方法.我需要进入此数组的字符串范围为4-70个字符.我所知道的每种方法都只改变了第二维,所以我最终得到了:
which works pretty well. But then i ran into my Problem: how do i keep track of the current point in the array? Following the if-check i would go for an else-statement that acts when $i is bigger than 0. But if i want to insert the next dimension of array, which would be 'D' in this case, i would need to select $array1['A'], for the next i would need $array1['A']['D'] etc. I wasn't able to find a way yet to do that. The strings i need to get into this array vary from 4-70 chars. Each method i know of only changed the 2nd dimension so i ended up with:
$array1('A'=>array ('A' =>array()));
$array1('A'=>array ('D' =>array()));
$array1('A'=>array ('A' =>array()));
$array1('A'=>array ('M' =>array()));
或由索引本身是数组引起的非法偏移错误.也许我在这里的方法是不可能的,但是我仍然认为我可能会问,以防我错过了一些东西.
or illegal offset-errors caused by the indexes being arrays themselves. Maybe my approach here is not possible, but i still thought i might ask in case i missed something.
在稍后阶段,im希望对所有字符串使用相同的数组,因此我基本上将Chars用作节点..如果已经存在作为第一个char的'A',那么我将跳过它并插入下一个字符串的第二个char放入"A"数组等.
In a Later stage im looking to use the same array for all strings so i basically use the Chars as nodes.. if 'A' as first char already exists i would then skip that and insert the 2nd char of the next string into the 'A'-Array etc.
预先感谢!
推荐答案
您可以为此使用递归函数.
You can use a recursive function for this.
function nest(string $str, int $i = 0) {
return isset($str[$i]) ? [$str[$i] => nest($str, $i + 1)] : ['result' => $str];
}
$result = nest($string);
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