解释printf中的评估顺序 [英] Explain the order of evaluation in printf

问题描述

main()
{
    int i=5;
    printf("%d%d%d%d%d%d",i++,i--,++i,--i,i);
}

输出为45545，但我不知道它是如何工作的.有人说函数调用中的参数从左到右被压入堆栈.

Output is 45545, but I don't how it is working. Some say that the arguments in a function call are pushed into the stack from left to right.

推荐答案

标准中未定义传递函数参数的顺序，该顺序由 cdecl 调用约定(很多C编译器用于x86体系结构)用于从右到左评估函数中的参数.

The order in which the parameters to a function are passed is not defined in the standard, and is determined by the calling convention used by the compiler. I think in your case, cdecl calling convention (which many C compilers use for x86 architecture) is used in which arguments in a function get evaluated from right to left.

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