正则表达式-C#中的2个字母和2个数字 [英] Regular Expression - 2 letters and 2 numbers in C#

问题描述

我正在尝试开发一个正则表达式来验证出现在我这里的字符串，例如:"TE33"或"FR56"或任何包含2个字母和2个数字的序列.

I am trying to develop a regular expression to validate a string that comes to me like: "TE33" or "FR56" or any sequence respecting 2 letters and 2 numbers.

前2个字符必须是字母，最后2个字符必须是数字.

The first 2 characters must be alphabetic and 2 last caracters must be numbers.

我尝试了许多组合，但没有成功.我尝试的最后一个:

I tried many combinations and I didn't have success. Last one I tried:

if(Regex.IsMatch(myString, "^[A-Za-z]{2}[0-9]{2}")){
}

推荐答案

您缺少结尾锚.

if(Regex.IsMatch(myString, "^[A-Za-z]{2}[0-9]{2}\z")) {
    // ...
}

这是一个演示.

如果您可以在首2个字母和后2个数字之间输入任何内容:

If you can have anything between an initial 2 letters and a final 2 numbers:

if(Regex.IsMatch(myString, @"^[A-Za-z]{2}.*\d{2}\z")) {
    // ...
}

这是一个演示.

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