XPath-如何选择节点的子元素? [英] XPath - how do you select the child elements of a node?

问题描述

我有一个包含XHTML表的XmlDocument.我想遍历它一次一次处理表单元格，但是下面的代码返回嵌套循环中的所有单元格，而不仅仅是返回当前行的所有单元格:

I have an XmlDocument containing a XHTML table. I'd like to loop through it to process the table cells one row at a time, but the code below is returning all the cells in the nested loop instead of just those for the current row:

XmlNodeList tableRows = xdoc.SelectNodes("//tr");
foreach (XmlElement tableRow in tableRows)
{
    XmlNodeList tableCells = tableRow.SelectNodes("//td");
    foreach (XmlElement tableCell in tableCells)
    {
        // this loops through all the table cells in the XmlDocument,
        // instead of just the table cells in the current row
    }
}

我做错了什么?谢谢

推荐答案

以."开头的内部路径.表示您要从当前节点开始.开头的"/" 始终从xml文档的根目录开始搜索，即使您在子节点上指定了它也是如此.

Start the inner path with a "." to signal that you want to start at the current node. A starting "/" always searches from the root of the xml document, even if you specify it on a subnode.

所以:

XmlNodeList tableCells = tableRow.SelectNodes(".//td");

甚至

XmlNodeList tableCells = tableRow.SelectNodes("./td");

，因为那些< td> 可能直接在该< tr> 之下.

as those <td>s probably are directly under that <tr>.

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