std :: stringstream与std :: string串联多个字符串 [英] std::stringstream vs std::string for concatenating many strings
问题描述
我知道 std :: stringstream
的优点之一是它是 std :: istream
,因此它可以接受来自定义的任何类型的输入运算符<<
到 std :: istream
,也来自原始类型.
I know one of the advantages of std::stringstream
is that it is a std::istream
so it may accept input from any type that defines operator<<
to std::istream
, and also from primitives types.
我将不使用 operator<<
;相反,我只是要连接许多字符串. std :: stringstream
的实现是否比连接许多字符串的 std :: string
更快?
I am not going to use operator<<
; instead I am just going to concatenate many strings. Does the implementation of std::stringstream
make it faster than std::string
for concatenating many strings?
推荐答案
没有理由期望 std :: string
的附加函数比 stringstream
'慢的插入功能. std :: string
通常只不过是可能的内存分配/复制以及将数据复制到内存中.即使对于基本的 write
调用, stringstream
也必须处理语言环境等问题.
There's no reason to expect std::string
's appending functions to be slower than stringstream
's insertion functions. std::string
will generally be nothing more than a possible memory allocation/copy plus copying of the data into the memory. stringstream
has to deal with things like locales, etc, even for basic write
calls.
此外, std :: string
提供了最小化或消除除第一次内存分配以外的任何方法的方法.如果您保留
足够的空间,则每次插入只不过是 memcpy
.对于 stringstream
,这实际上是不可能的.
Also, std::string
provides ways to minimize or eliminate anything but the first memory allocation. If you reserve
sufficient space, every insertion is little more than a memcpy
. That's not really possible with stringstream
.
即使它比 std :: string
的附加函数要快,您仍然必须将字符串从 stringstream
中复制出来用它做点事.这是另一个分配+副本,您无需使用 std :: string
.尽管至少C ++ 20似乎可以消除这种特殊需求.
Even if it were faster than std::string
's appending functions, you still have to copy the string out of the stringstream
to do something with it. So that's another allocation + copy, which you won't need with std::string
. Though at least C++20 looks set to remove that particular need.
如果您需要 formatting 格式,则应该使用 std :: stringstream
,而不仅仅是将一些字符串粘贴在一起.
You should use std::stringstream
if you need formatting, not just for sticking some strings together.
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