将字符串转换为char 2d数组 [英] Convert string to char 2d array
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问题描述
我想知道是否有人知道如何将字符串转换为2d数组?这是我的尝试:
I was wondering does anyone know how to convert a string into a 2d array? This was my attempt:
string w;
char s[9][9];
int p=0;
getline(cin, w);
while(p != w.size())
{
for (int k = 0; k < 9; k++)
{
for(int j = 0; j < 9; j++)
{
s[k][j] = w[p];
p++;
}
}
}
cout << "nums are: " << endl;
for(int k = 0; k < 9; k++)
{
for(int j = 0; j <9; j++)
{
cout << s[k][j];
}
}
但是数字不能正确打印出来.我希望s [k] [j]打印出w中的所有内容,但它只是打印出乱码.我还注意到,如果我做字符串[81],那么我会收到很多错误.有人可以帮我吗?谢谢.
But the numbers don't print out correctly. I want s[k][j] to print out everything in w but it simply prints out gibberish. I also noticed if i do string[81] then I get a whole bunch of errors. Could anyone help me? Thanks.
推荐答案
尝试一下:
const int NUM_ROWS = 9;
const int NUM_COLS = 9;
string w;
char s[NUM_ROWS][NUM_COLS];
getline(cin, w);
if (w.size() != (NUM_ROWS * NUM_COLS))
{
cerr << "Error! Size is " << w.size() << " rather than " << (NUM_ROWS * NUM_COLS) << endl;
exit(1);
}
for (int count = 0; count < w.size(); count++)
{
if (!isdigit(w[count]) && w[count] != '.')
{
cerr << "The character at " << count << " is not a number!" << endl;
}
}
for (int row = 0; row < NUM_ROWS; row++)
{
for(int col = 0; col < NUM_COLS; col++)
{
s[row][col] = w[col + (row * NUM_COLS)];
}
}
cout << "Nums are: " << endl;
for(int row = 0; row < NUM_ROWS; row++)
{
for(int col = 0; col < NUM_COLS; col++)
{
cout << s[row][col] << " ";
}
cout << endl;
}
基于我们的聊天,您可能想要这样做:
Based on our chat, you might want this:
const int NUM_ROWS = 9;
const int NUM_COLS = 9;
string w;
char s[NUM_ROWS][NUM_COLS];
while (!cin.eof())
{
bool bad_input = false;
getline(cin, w);
if (w.size() != (NUM_ROWS * NUM_COLS))
{
cerr << "Error! Size is " << w.size() << " rather than " << (NUM_ROWS * NUM_COLS) << endl;
continue;
}
for (int count = 0; count < w.size(); count++)
{
if (!isdigit(w[count]) && w[count] != '.')
{
cerr << "The character at " << count << " is not a number!" << endl;
bad_input = true;
break;
}
}
if (bad_input)
continue;
for (int row = 0; row < NUM_ROWS; row++)
{
for(int col = 0; col < NUM_COLS; col++)
{
s[row][col] = w[col + (row * NUM_COLS)];
}
}
cout << "Nums are: " << endl;
for(int row = 0; row < NUM_ROWS; row++)
{
for(int col = 0; col < NUM_COLS; col++)
{
cout << s[row][col] << " ";
}
cout << endl;
}
}
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