如何在C ++中将整数数组转换为IP地址? [英] How to convert an integer array into an ip address in c++?

问题描述

我有一个数组ipAddress [4]，其中包含4个整数值.127,0,0,1，我需要将其转换为字符串"127.0.0.1".

I have an array ipAddress[4] with 4 integer values e.g. 127,0,0,1 and I need to convert it to a string "127.0.0.1".

我该怎么做?

为澄清起见，我稍后需要将此功能与功能输入进行比较.我不想在屏幕上打印出来.

Just to clarify, I need this at a later point to compare with an input from a function. I do not want to print this out on the screen.

推荐答案

一种方法是:

char buf[16];
snprintf( buf, sizeof buf, "%d.%d.%d.%d",
    ipAddress[0], ipAddress[1], ipAddress[2], ipAddress[3] );

我个人觉得这比涉及循环和多个函数调用的10行解决方案更为优雅，其他人会不同意！

Personally I find this more elegant than 10-line solutions involving loops and multiple function calls, others will disagree!

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