从文件C ++读取数字 [英] Reading numbers from file c++

问题描述

我想从文本文件中读取数字.该文件包含以下数字.

I want to read numbers from text file. The file contains following numbers.

3 5 7 9 20 25 30 40 55 56 57 60 621 4 7 11 14 25 44 47 55 57 100-5 100 1000 1005-12 1000 1001

用空格分隔数字.我必须编写一些代码才能读取此内容，但问题是读取行尾的数字不正确，并且我不知道如何正确读取它们(CRLF字符有问题)；有人可以帮我弄这个吗?这是我的代码.

Space separates numbers. I had to make some code to read this but the problem is that reading the numbers at the end of line are not correct and I don't know how to read them properly(Problem with CRLF chars); Can someone help me with this? Here is my code.

标题base.h

#include <iostream>
#include <fstream>
#include <string.h>
#include <cstdlib>
using namespace std;

class L
{
    public:
    int value;
};

class t
{
public:
    L *line;
    t(){
        line = new L[10000];
    }
};

class baza
{
public:
    ifstream in;
    ofstream out;
    string lines;
    char word1[1] ;
    int wordint;
    char tab[255];
    int *tab2;

    int x;
    int y;
    int z;
    int a;
    int b;
    int c;
    int ile;

    int multiplier;
    bool negative ;
    int negative;
    t *table;

    base();
};

这是base.cpp

Here are base.cpp

#include "base.h"

base::base()
{
    wordint=0;
    a=2000;
    b=0;
    tab2 =new int [a];
    x=0;
    y=0;
    z=0;

    for(int i=0;i<a;i++)
    {
        tab2[i]=0;

    }
    multiplier=1;
    negative =false;
    negative1=-1;
    lines="0";
    ile=0;
    in.open("in.txt");   //open file

    do   
    {
        getline(in,lines);
        if(lines!="0")      //how many lines is in the file
        {
            ile++;
        }
    } while(in.eof()!=true);
    in.close();
    tablica =new t[ile];
    tab5 = new int[ile];
    in.open("in.txt");

    for(int i=0;i<ile;i++)
    {
        do
        {
            in.get(word1[0]);
            if(word1[0]==45)   // check if sign is negative
            {
                word1[0]=0;
                negative=true;
                in.get(word1[0]);
            }
            if(word1[0]!= 10)  //check if  not LF
            {
                if(word1[0]!=' ')  //check if not space
                {
                    tab[x]= word1[0];
                    x++;
                }
            }
            if(word1[0]==' ')  //if space then convert from char to int 
            {
                y=x-1;
                do {
                    word1[0]=tab[y];
                    wordint=atoi(word1);
                    wordint=wordint*multiplier;
                    tab2[z]=tab2[z]+wordint;
                    y--;
                    multiplier=multiplier*10;
                } while(y>=0);
                x=0;
                multiplier=1;
                if(negative==true)  //check if negative
                {
                    tab2[z]=tab2[z]*negative1;
                    negative=false;
                }
                z++;
                c=z;
                tab5[i]=c;
            }
            /**if(word1[0]== '10')  //its not work but same as above only check if LF
            {
                y=x-1;
                do{
                    word1[0]=tab[y];
                    wordint=atoi(word1);
                    wordint=wordint*multiplier;
                    cout<<"dupa";
                    tab2[z]=tab2[z]+wordint;
                    y--;
                    multiplier=multiplier*10;
                } while(y>=0);
                x=0;
                multiplier=1;
                if(negative==true)  //check if negative
                {
                    tab2[z]=tab2[z]*negative1;
                    negative=false;
                }
                z++;
                c=z;
                tab5[i]=c;
            }*/

        } while(word1[0]!=10);
        for(int j=0;j<z;j++)      //write to table
        {
            table[i].line[j].value=tab2[j];
            cout<< table[i].line[j].value<<endl;
            tab2[j]=0;
        }
        z=0;
    }
}

推荐答案

您应该简单地组合以下示例:

You should simply combine examples as below:

• 首先，读取文件的所有行(使用逐行读取文件)
• 然后，拆分得到的字符串(使用在C ++中拆分字符串?)
• 最后，将每个元素转换为数字(使用将字符串转换为int C ++ ).

您的代码看上去比您发布的代码更聪明，并且可以正常工作.

Your code will look way smarter than what you posted and should work.

这篇关于从文件C ++读取数字的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！