C4473结构分配警告 [英] C4473 warning for structure assignment
问题描述
我目前正在从事一项作业,并且好奇该警告在编译时是什么以及如何解决.它会生成,但是在我调试时会出现错误屏幕.以下是出现的警告.
I am currently working on an assignment and was curious what this warning is when compiling and how to remedy it. It will build but when I debug it will get an error screen. Below is the warning that comes up.
1> c:\ users \ cesteves \ documents \ c编程\库存\库存\库存.cpp(48):警告C4473:'scanf_s':传递的格式字符串参数不足
1>c:\users\cesteves\documents\c programming\inventory\inventory\inventory.cpp(48): warning C4473: 'scanf_s' : not enough arguments passed for format string
注意:占位符及其参数需要2个可变参数,但提供了1个
note: placeholders and their parameters expect 2 variadic arguments, but 1 were provided
注意:格式字符串要求缺少可变参数2'%s'注意:此参数用作缓冲区大小
note: the missing variadic argument 2 is required by format string '%s' note: this argument is used as a buffer size
#include "stdafx.h"
#include <stdio.h>
void main()
{
struct date {
int day;
int month;
int year;
};
struct details {
char name[20];
int price;
int code;
int qty;
struct date mfg;
};
struct details item[50];
int n, i;
printf("Enter number of items:");
scanf_s("%d", &n);
for (i = 0; i < n; i++) {
printf("Item name: \n");
scanf_s("%s", item[i].name);
printf("Item code: \n");
scanf_s("%d", &item[i].code);
printf("Quantity: \n");
scanf_s("%d", &item[i].qty);
printf("price: \n");
scanf_s("%d", &item[i].price);
printf("Manufacturing date(dd-mm-yyyy): \n");
scanf_s("%d-%d-%d", &item[i].mfg.day, &item[i].mfg.month, &item[i].mfg.year);
}
printf(" ***** INVENTORY ***** \n");
printf("----------------------------------------------------------------- - \n");
printf("S.N.| NAME | CODE | QUANTITY | PRICE| MFG.DATE \n");
printf("----------------------------------------------------------------- - \n");
for (i = 0; i < n; i++)
printf("%d %-15s %-d %-5d %-5d%d / %d / %d \n", i + 1, item[i].name, item[i].code, item[i].qty,item[i].price, item[i].mfg.day, item[i].mfg.month,item[i].mfg.year);
printf("----------------------------------------------------------------- - \n");
}
推荐答案
您应提供缓冲区的大小.例如,如果您仅读取一个字符,则应该是这样的:
You should provide a size of the buffer. For example, if you reading only one char, it should be like this:
char c;
scanf_s("%c", &c, 1);
请阅读参考!
此外, structs
很高兴放在 main()
之前.关于 structs的基本用法,我始终牢记示例
.
Also, structs
are nice to be placed before main()
. I always have my example in mind, on the basic usage of structs
.
在您的情况下,main的原型应为 int main(void)
.检查以下内容: int main()vs void main()in C
The prototype of main should be int main(void)
in your case. Check this: int main() vs void main() in C
在您的代码中,更改以下内容:
In your code, change this:
scanf_s("%s", item[i].name);
对此:
scanf_s("%s", item[i].name, 20);
因为这个:
struct details {
char name[20];
..
其余的都做同样的事情.
Do the same for the rest..
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