在C ++中读取大的.txt文件时出现奇怪的错误 [英] Weird error when reading a large .txt file in c++

问题描述

我正在尝试读取一个非常大的.txt文件，该文件具有128x128x128 = 2097152行(线性化的3d空间)，每行仅包含一个0或1(不要问为什么)...我将代码缩减为几行，似乎当我确定行和增量时，一切进展顺利...但是，只要我想将数据放入足够允许的数组中，行读取就会在i = 12286处停止...

i'm trying to read a very large .txt file that has 128x128x128=2097152 lines (linearised 3d space) containing only one 0 or 1 by line (Don't ask why)... I mowed down my code to a few lines and it seems that when I cout the line and the increment, everything goes well... but as soon as I want to put the data inside a sufficiently allowed array, the line reading stops at i=12286...

这是代码

int dim = nbvox[0]*nbvox[1]*nbvox[2];
float* hu_geometry = new float(dim);
int* hu_temp = new int(dim);
string line;

int i = 0;


ifstream in(hu_geom_file.c_str());
if(in.is_open())
{
  while(getline(in, line))
  {

    hu_temp[i] = stoi(line);
    cout << "i= " << i << " line= " << line << " hu_temp= " << hu_temp[i] << endl;
    i++;
  }
  cout << __LINE__ << " i=" << i << endl;
  in.close();
  cout << __LINE__ << endl;
}
else cout << "Unable to open " << hu_geom_file << endl;

这是在得到错误之前我得到的最后一个输出...这很奇怪，因为每当我在while内注释hu_temp行时，仅cout即可运行2097152.

Here's the last output I get before getting the error... which is very strange because whenever I comment the hu_temp line inside the while, the cout alone works up to 2097152.

i= 12276 line= 0 hu_temp= 0
i= 12277 line= 0 hu_temp= 0
i= 12278 line= 0 hu_temp= 0
i= 12279 line= 0 hu_temp= 0
i= 12280 line= 0 hu_temp= 0
i= 12281 line= 0 hu_temp= 0
i= 12282 line= 0 hu_temp= 0
i= 12283 line= 0 hu_temp= 0
i= 12284 line= 0 hu_temp= 0
i= 12285 line= 0 hu_temp= 0
115 i=12286
*** Error in `G4Sandbox': free(): invalid pointer: 0x0000000001ba4c40 ***
Aborted (core dumped)

推荐答案

float* hu_geometry = new float(dim);
int* hu_temp = new int(dim);

是包含值 dim 的1个字符的数组.在某些时候，您遇到MMU边界并随机崩溃.

those are 1-char arrays containing the value dim. At some point you're hitting a MMU boundary and crashes randomly.

您要写:

float* hu_geometry = new float[dim];
int* hu_temp = new int[dim];

，或者对于预先分配了 dim 个元素

or maybe better with vectors, pre-allocated with dim elements

#include <vector>
std::vector<float> hu_geometry(dim);
std::vector<int> hu_temp(dim);

或在开始时未分配:

std::vector<int> hu_temp;

并在您的代码中:

hu_temp.push_back(stoi(line));

( hu_temp.size()给出了大小和许多很好的功能，这些功能可以更好地描述此处)

(hu_temp.size() gives the size and a lot of very nice features better described here)

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