省略数据类型(例如"unsigned"而不是"unsigned int") [英] Omitting the datatype (e.g. "unsigned" instead of "unsigned int")

问题描述

我知道，如果在C/C ++代码中以以下方式省略数据类型声明: unsigned test = 5; ，则编译器会自动将此变量设为int(在这种情况下为unsigned int).我听说这是C标准，它将在所有编译器中都可以使用.

I know that if the data type declaration is omitted in C/C++ code in such way: unsigned test=5;, the compiler automatically makes this variable an int (an unsigned int in this case). I've heard that it's a C standard and it will work in all compilers.

但是但是我也听说这样做是不正确的.

But I've also heard that doing this is considered a bad practice.

您怎么看?我应该真的输入 unsigned int 而不是仅仅输入 unsigned 吗?

What do you think? Should I really type unsigned int instead of just unsigned?

short ， long 和 long long 也是数据类型吗?

Are short, long and long long also datatypes?

推荐答案

unsigned 是数据类型！碰巧是 unsigned int 的别名.

在编写 unsigned x; 时，不省略任何数据类型.

When you’re writing unsigned x; you are not omitting any data type.

这与C中存在的默认 int "(但在C ++中没有)完全不同，在C中您实际上忽略了声明的类型，C会自动推断该类型为int .

This is completely different from "default int" which exists in C (but not in C++!) where you really omit the type on a declaration and C automatically infers that type to be int.

关于样式，我个人更喜欢露骨，因此要编写 unsigned int .另一方面，我目前正在图书馆中，习惯上只写 unsigned ，所以我这样做.

As for style, I personally prefer to be explicit and thus to write unsigned int. On the other hand, I’m currently involved in a library where it’s convention to just write unsigned, so I do that instead.

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